Sum of two numbers is -17. Their difference is 41. Find the numbers

Mathematics

1 answer:

wel3 years ago

3 0

Answer:

$Suppose~the~two~numbers~are~x~and~y.\\From~the~first~condition,\\x+y=-17...........(1)\\From~the~second~condition,\\x-y=41.............(2)\\Adding~eq^n(1)~and~eq^n(2),~we~get,\\x+y+x-y=-17+41\\or, 2x = 24\\or, x=12\\Substituting~x=12~in~eq^n(2),\\y = -17-x = -17-12 = -29$

$So,~the~two~numbers~are~12~and~-29.$

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What is a cubic polynomial function with zeros 3,3 and -3? show your work.

Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

$(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0$