Answer:
Number of moles = mass/molar mass
Explanation:
Given data:
mass of Al = 11 g
Moles = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of aluminium is 27 g/mol
Now we will put the values in formula.
Number of moles = 11 g/ 27 g/mol
Number of moles = 0.41
The number of moles in 11 g Al are 0.41 mol.
20 molecules minus ten degrees equals 1001
Answer:
306.6g/mol
Explanation:
To calculate molecular weight you need to know how many grams ou have in a determined amount of moles of substance. As you have the mass of the sample (1.42g), you need to find how many moles are, as follows:
The reaction of the acid HX with the base YOH is:
HX + YOH → H₂O + YX
<em>1 mole of acid reacts per mole of base.</em>
<em />
In a titration, the solution turned pink when moles base = moles acid.
Moles of base that the student added (Using the volume and molarity of the solution) are:
32.48mL = 0.03248L ₓ (0.1426 moles base / L) = 0.004632 moles of base
As the titration is in equivalence point, there are 0.004632 moles of the acid
Molecular weight (Ratio between grams of sample and its moles) is:
1.42g / 0.004632 moles =
<h3>306.6g/mol</h3>
First one is reactants and then second one is products
Answer:
-79.8 × 10⁴ J/mol
Explanation:
<em>Arsine, AsH₃, is a highly toxic compound used in the electronics industry for the production of semiconductors. Its vapor pressure is 35 Torr at 111.95 °C and 253 Torr at 83.6 °C.</em>
<em />
Then,
P₁ = 35 torr
T₁ = 111.95 + 273.15 = 385.10 K
P₂ = 253 torr
T₂ = 83.6 + 273.15 = 356.8 K
We can calculate the standard enthalpy of vaporization (ΔH°vap) using the two-point Clausius-Clapeyron equation.
where,
R is the ideal gas constant
