1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rina8888 [55]
3 years ago
6

Where can you find most of Earth's liquid freshwater?

Chemistry
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

Where can you find most of Earth's liquid freshwater?

Explanation:

Over 68 percent of the fresh water on Earth is found in icecaps and glaciers, and just over 30 percent is found in ground water. Only about 0.3 percent of our fresh water is found in the surface water of lakes, rivers, and swamps.

Hope that helped, i also have snap if you need me.

You might be interested in
What is the relationship between a mole and Avogadro number
docker41 [41]
A mole contains Avogadro’s number of particles of a substance.
4 0
3 years ago
Read 2 more answers
Sixty-three percent of the number 1059 is
slega [8]
667.17 (0.63x1059) shsbsbsb
4 0
3 years ago
Read 2 more answers
A 25.00 ml solution of sulfuric acid H2SO4 is titrated to phenolphthalein end point with 27.00 ml of 1.700 M KOH
Nastasia [14]
<h3>Answer:</h3>

0.918 M

<h3>Explanation:</h3>

Assuming the question requires we calculate the Molarity of sulfuric acid:

We are given:

  • Volume of the acid, H₂SO₄ = 25.00 ml
  • Volume of the base, KOH = 27.00 mL
  • Molarity of the base, KOH is 1.70 M

We can calculate the molarity of the acid using the following steps;

<h3>Step 1: Write the chemical equation for the reaction.</h3>

The reaction is an example of a neutralization reaction where a base reacts with an acid to form salt and water.

Therefore, the balanced equation will be;

H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)

<h3>Step 2: Determine the moles of the base, KOH </h3>

When given molarity and the volume of a solution, the number of moles can be calculated by multiplying molarity with volume.

Number of moles = Molarity × Volume

                             = 1.700 M × 0.027 L

                              = 0.0459 moles

Thus, moles of KOH used is 0.0459 moles

<h3>Step 3: Determine the number of moles of the Acid, H₂SO₄</h3>

From the reaction, 1 mole of the acid reacts with 2 moles of KOH

Therefore, the mole ratio of H₂SO₄ to KOH is 1 : 2

Thus, moles of H₂SO₄ = Moles of KOH ÷ 2

                                     = 0.0459 moles ÷ 2

                                     = 0.02295 moles

<h3>Step 4: Calculate the molarity of the Acid </h3>

Molarity is the concentration of a solution in moles per liter

Molarity = Moles ÷ Volume

Molarity of the acid = 0.02295 moles ÷ 0.025 L

                                = 0.918 M

Thus, the molarity of the acid, H₂SO₄ is 0.918 M

5 0
3 years ago
Someone plz help me
a_sh-v [17]

Answer:

A experimental investigation

3 0
2 years ago
Balance and classify this reaction:<br> C6H6 +02 →CO2 +H₂O
laila [671]
This is a combustion reaction.
2C6H6 + 9O2➡️ 6CO2 + 6H2O
6 0
3 years ago
Other questions:
  • What is all matter made up of?<br> A. carbon<br> B. atoms<br> C. metal<br> D. cells
    5·2 answers
  • What is the final chemical equation from the following intermediate chemical equations?
    12·1 answer
  • What is happening in this diagram?
    12·1 answer
  • Do all titrations of a strong base with a strong acid have the same ph at the equivalence point?
    5·1 answer
  • 1) What is the concentration of the salt solution that has 15 g of salt in 137 ml of<br> water?
    12·1 answer
  • How does an object become electrically charged?will give brainliest
    12·1 answer
  • Hello
    7·2 answers
  • How much NaOH (in moles) must be added to 1 L of a buffer solution that is 1.8 M in acetic acid and 1.2 M in sodium acetate to r
    9·1 answer
  • С
    14·1 answer
  • How can one show that elements that have different appearances have similar chemical properties?​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!