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Alenkinab [10]
3 years ago
11

For y=2/3 x-2 what is the range of this function where the domain is 3 to 12

Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

Range = {0,2/3,1 1/3, 2, ...}

Step-by-step explanation:

The range is the output so the y values, when x = 3 then

y = \frac{2}{3}(3) - 2 so y = 0

y = \frac{2}{3}(4) - 2 so 8/3 - 6/3 is 2/3 so y = 2/3

y = \frac{2}{3}(5) - 2 so 10/3 - 6/3 is 4/3 so y = 4/3 or 1 1/3

y = \frac{2}{3}(6) - 2 so 12/3 - 6/3 is 6/3 so  y = 2 and so on....

Now you try the rest

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Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i
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Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in \frac{6}{5} hr

Pump A and C can fill tank in \frac{3}{2} hr

Pump B and C can fill tank in 2 hr

Let A be the total hr taken A therefore rate of A=\frac{1}{A} /hr

Let B be the total hr taken B therefore rate of B=\frac{1}{B} /hr

Let C be the total hr taken C therefore rate of C=\frac{1}{C} /hr

\frac{1}{A}+\frac{1}{B}=\frac{5}{6}-----1

\frac{1}{B}+\frac{1}{C}=\frac{1}{2}-----2

\frac{1}{A}+\frac{1}{C}=\frac{2}{3}-----3

Adding 1,2 & 3

2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1

thus time taken by A,B and C combined is 1 hr

7 0
3 years ago
You have a credit card with a balance of $2,856.74 at a 14.75% APR. You decide to put $629.63/month toward reducing your debt. H
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What is 7 times the sum of a squared and b minus 4 times the sum of a squared and b
spayn [35]
<span><span>The sum of a squared and b is given by
a^2+b

</span>7 times the sum of a squared and b is given by
</span><span>7(a^2+b)
while 4 times the sum of a squared and b is given by
</span>4(a^2+b)

Therefore, <span>7 times the sum of a squared and b minus 4 times the sum of a squared and b is given by

7(a^2+b)-4(a^2+b)=3(a^2+b)</span>
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BD bisects /ABC. Find the value of x.
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Answer:

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Step-by-step explanation:

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3 years ago
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Lake has a total of $10,000 to invest in two accounts. One account earns 1% simple interest, and the other earns 10% simple inte
Elza [17]

Answer:

  1. $8000 at 1%
  2. $2000 at 10%

Step-by-step explanation:

It often works well to let a variable represent the amount invested at the higher rate. Then an equation can be written relating amounts invested to the total interest earned.

__

<h3>setup</h3>

Let x represent the amount invested at 10%. Then 10000-x is the amount invested at 1%. The total interest earned is ...

  0.10x +0.01(10000 -x) = 280

<h3>solution</h3>

Simplifying gives ...

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  0.09x = 180 . . . . . . . subtract 100

  x = 2000 . . . . . . divide by 0.09

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<h3>1.</h3>

$8000 should be invested in the 1% account

<h3>2.</h3>

$2000 should be invested in the 10% account

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2 years ago
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