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Sunny_sXe [5.5K]
3 years ago
12

Add the two expressions 6q+1 and q+11 Enter your answer into the box

Mathematics
2 answers:
MAXImum [283]3 years ago
8 0

Answer:

7q + 12

Step-by-step explanation:

In-s [12.5K]3 years ago
7 0

Answer:

7q + 12

Step-by-step explanation:

6q + 1 + q + 11

add like terms. add 6q and q together and then add 1 and 11 together

6q + q + 1 + 11

7q + 12

7q + 12 is your answer. i hope this helps :)

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Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters
s344n2d4d5 [400]

The various answers to the question are:

  • To answer 90% of calls instantly, the organization needs four extension lines.
  • The average number of extension lines that will be busy is Four
  • For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

a)

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$

Generally, the equation for is  mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

b)

The probability that a call will receive a busy signal if four extensions lines are used is,

P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$

Therefore, the average number of extension lines that will be busy is Four

c)

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about signal

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3 0
2 years ago
Type the integer that makes the following subtraction sentence true:<br> -57 - ? = -151
posledela

Answer:

94

Step-by-step explanation:

Its pretty simple,

The easiest way to find the missing number is to do 151-57, which = 94

8 0
3 years ago
What is the value of x?
a_sh-v [17]

In my knowledge

x = 24²+7²

= 576+49= 625

x= sqroot of 625

x = 25 (By Pythagoras Theorem)

Hope it helps

3 0
3 years ago
5.6 as an improper fraction simplified?
Phoenix [80]
As a fraction, it would be 5 6/10. Then you multiply the denominator by the whole number 5x10 and add the numerator. So,
10X5+6=56
56/10
divide by 2
28/5 is the simplified version
8 0
3 years ago
The radius of a cylinder is 3 yards, and the total surface area is 320 square yards. Which of the following is the closest to th
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The answer is D I think
5 0
3 years ago
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