Answer:
The financial advisor is not using percentage properly.
Percentage loss=2%
Step-by-step explanation:
original amount invested=$11000
By the end of the first year, there was a decrease by 30% over the original amount.
This implies that the amount invested at after the end of the first year or at the beginning of the second year
=$7,700
This amount has increased by 40%
=$10,780
The financial advisor is not using percentage properly.
This is because the decrease was on the original amount meanwhile the increase was not on the original amount. The increase was rather on an amount less than the original amount .
Since the original amount invested is greater than the amount at the end of the second year, there was a loss
Hence percentage loss
Answer:
Given that, Vasudevan invested ₹ 60,000
For Compound Interest (C.I.)
A = P[1 + (r/100)]n
P = ₹ 60,000
n = 6 months and 1 year
R = 12% p.a. compounded half-yearly
where , A = Amount, P = Principal, n = Time period and R = Rate percent
(i) For easy calculation of compound interest, we will put Interest Rate as 6% half-yearly and n = 1.
Compound Interest to be paid for 6 months
A = P[1 + (r/100)]n
A = 60000[1 + (6/100)]1
A = 60000[(100/100) + (6/100)]
A = 60000 × (106/100)
A = 60000 × 1.06
A = ₹ 63600
(ii) Compound Interest to be paid for 12 months (1 year) compounded half yearly.
So, assume n = 2, r = 6%
A = P[1 + (r/100)]n
A = 60000[1 + (6/100)]2
A = 60000[(100/100) + (6/100)]2
A = 60000 × (106/100) × (106/100)
A = 60000 × (11236/10000)
A = 60000 × 1.1236
A = ₹ 67416
He should survey the people who most often attend the game
Answer: False
Explanation:
By definition, the z-score of the random variable, x, is
where
μ = the population mean
σ = the population standard deviation
Because only the sample mean and the sample standard deviations are known, we cannot calculate the z-score. Instead, we can calculate the Student t-test statistic.
I haven’t done math in a year but to solve for X I think the answer will be X=10
