Answer:
1/2
Step-by-step explanation:
A=p(1+i/m)^mn
A=1,200×(1+0.03÷2)^(2×7)
A=1,478.11
Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Answer:
Step-by-step explanation:
(-5,-3) is a point on the graph.
f⁻¹(-3) = -5
Answer:
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Step-by-step explanation:
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