Answer:
See below
Step-by-step explanation:
1.
-6(a + 8)
Distribute the -6.
-6a - 48
2.
4(1 + 9x)
Distribute the 4.
4 + 36x or 36x + 4
3.
6(-5n + 7)
Distribute the 6.
-30n + 42
4.
(9m + 10) * 2
Rewrite.
2(9m + 10)
Distribute the 2.
18m + 20
5.
(-4 - 3n) * -8
Rewrite.
-8(-4 - 3n)
Distribute the -8.
32 + 24n or 24n + 32
6.
8(-b - 4)
Distribute the 8.
-8b - 32
7.
(1 - 7n) * 5
Rewrite.
5(1 - 7n)
Distribute the 5.
5 - 35n or -35n + 5
8.
-6(x + 4)
Distribute the -6.
-6x - 24
9.
5(3m - 6)
Distribute the 5.
15m - 30
10.
(-6p + 7) * -4
Rewrite.
-4(-6p + 7)
Distribute the -4.
24p - 28
11.
5(b - 1)
Distribute the 5.
5b - 5
12.
(x + 9) * 5
Rewrite.
5(x + 9)
Distribute the 5.
5x + 45
Answer:
Sides are x and x + 3.5 cm
Perimeter = 2(x + (x + 3.5))cm
4x +7 = 67
x = 15cm Answer
Step-by-step explanation:
HOPE THIS HELPED!
Answer:
54
Step-by-step explanation:
Answer:
The speed of the first train is 45 mph and the speed of the second train is 75 mph
Step-by-step explanation:
Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).
The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles
The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles
Since the second train overtakes the first at 6:00 pm, hence:
3x + 90 = 5x
2x = 90
x = 45
Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).
<u>Correct</u><u> </u><u>question</u><u>:</u><u>-</u>
<u>Prove </u><u>that </u><u>tan9.</u><u>t</u><u>a</u><u>n</u><u>1</u><u>7</u><u>.</u><u>t</u><u>a</u><u>n</u><u>4</u><u>5</u><u>.</u><u>t</u><u>a</u><u>n</u><u>7</u><u>3</u><u>.</u><u>t</u><u>a</u><u>n</u><u>8</u><u>1</u><u>=</u><u>1</u>
<u>LHS</u>





