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ivann1987 [24]
3 years ago
7

The slope of a line is 2 and the point (1, 1) lies on the line. What is the y-intercept of this line? (0, -1) (0, 5) (-2, 0)

Mathematics
1 answer:
artcher [175]3 years ago
4 0

Answer:

(0, -1)

Step-by-step explanation:

It's helpful if we think of slope in the context of rise over run.

Since the point (1, 1) lies on the line, because of the slope 2, if we subtract x by 1 to get to x = 0, then we'll be subtracting y by 2.

By that logic, the answer must be (0, -1).

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Step-by-step explanation:

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Find the remainder when f(x) = x3 − 14x2 + 7x − 10 is divided by x − 3. 184 164 −88 −122
Fudgin [204]

Answer:

122

Step-by-step explanation:

For this case we must build a quotient that, when multiplied by the divisor, eliminates the terms of the divide until it reaches the remainder.

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5 0
3 years ago
27. The average hourly wage of workers at a fast food restaurant is $7.25/hr
morpeh [17]

Answer:

0.0668 = 6.68% probability that the worker earns more than $8.00

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.

This means that \mu = 7.25, \sigma = 0.5

If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?

This is 1 subtracted by the pvalue of Z when X = 8. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 7.25}{0.5}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that the worker earns more than $8.00

8 0
3 years ago
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