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2 years ago

7

1. Find the sum of -9g and 6g + 3

2 answers:

mina [271]2 years ago

7 0

Answer:

-3g + 3

Step-by-step explanation:

-9g + 6g + 3

combine like terms

-3g + 3

Hope this Helps!!!

hammer [34]2 years ago

4 0

Answer:

-3g + 3

Step-by-step explanation:

This would be the answer because if we add 6g to -9g then we would have -3g since 3 and 3 are not like terms then we can just add them like this -3g+3

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Solve for x. 4x + 5 = 20<br> a X = 5/4<br> b X = 15/4<br> c X = 3.5<br> d X = 15/3

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Step-by-step explanation:

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3 years ago

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KatRina [158]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Phonics is an instructional method in which children are taught to connect sounds with letters or groups of letters. A sample of

Fantom [35]

Answer:

A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645\frac{23.44}{\sqrt{141}}$

$M = 3.25$

The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.

The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.

A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).

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3 years ago