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Evgesh-ka [11]
3 years ago
14

3.9p − 7.53 = 8p + 9.77 + 8.94

Mathematics
1 answer:
Tamiku [17]3 years ago
8 0

The answer is P= -6.4 Good luck

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Someone help me please-
Helen [10]

Answer:

Rectangle 11.59 sqft

Rectangle 36 sqft

Polygon 47.59 sqft

Step-by-step explanation:

8 0
3 years ago
Wayne Gretsky scored a Poisson mean six number of points per game. sixty percent of these were goals and forty percent were assi
BartSMP [9]

Answer:

a) The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

b) 0.05 = 5% probability that he has four goals and two assists in one game

Step-by-step explanation:

In hockey, a point is counted for each goal or assist of the player.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval. The standard deviation is the square root of the mean.

(a) Find the mean and standard deviation for the total revenue he earns per game.

60% of six are goals, which means that 60% of the time he earned 3K.

40% of six are goals, which means that 40% of the time he earned 1K.

The mean is:

\mu = 6*0.6*3 + 6*0.4*1 = 13.2

The standard deviation is:

\sigma = \sqrt{\mu} = \sqrt{13.2} = 3.63

The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

(b) What is the probability that he has four goals and two assists in one game

Goals and assists are independent of each other, which means that we find the probability P(A) of scoring four goals, the probability P(B) of getting two assists, and multiply them.

Probability of four goals:

60% of 6 are goals, which means that:

\mu = 6*0.6 = 3.6

The probability of scoring four goals is:

P(A) = P(X = 4) = \frac{e^{-3.6}*(3.6)^{4}}{(4)!} = 0.19122

Probability of two assists:

40% of 2 are assists, which means that:

\mu = 6*0.4 = 2.4

The probability of getting two assists is:

P(B) = P(X = 2) = \frac{e^{-2.4}*(2.4)^{2}}{(2)!} = 0.26127

Probability of four goals and two assists:

P(A \cap B) = P(A)*P(B) = 0.19122*0.26127 = 0.05

0.05 = 5% probability that he has four goals and two assists in one game

5 0
3 years ago
Which expression is equivalent to 36a-12b? <br><br> 3(6a-2b). 6(6a-2b). 3(6a+2b). 6(6a+2b)
Maurinko [17]

Answer:

6(6a-2b)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the slope of the line graphed below.
Phantasy [73]

Answer:

Slope: -3/5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
729 = __ to the 3rd power
TEA [102]
The answer is 9 because 9 to the second power is 81 and 81*9 = 729 :)))
i hope this is helpful 
have a nice day 
3 0
3 years ago
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