Answer:
b
Step-by-step explanation:
a^3b^2c = b(a^3bc)
5bc = b(5c)
15a^2b = b(15a^2)
GCF = b
0.0909090909 Is the answer my friend plz mark brainliest
Answer:

Step-by-step explanation:
From figure,

In triangle 

![\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]](https://tex.z-dn.net/?f=%5CRightarrow%20%28a%2Bb%29%5E2%3D%28a-b%29%5E2%2B%28O%27%20D%29%5E2%5C%5C%5CRightarrow%20a%5E2%2Bb%5E2%2B2ab-a%5E2-b%5E2%2B2ab%3D%28O%27%20D%29%5E2%5C%5C%5CRightarrow%204ab%3D%28O%27%20D%29%5E2%5C%5C%5CRightarrow%20O%27D%3D2%5Csqrt%7Bab%7D%20%5C%5C%5CRightarrow%20O%27%20D%3D2%5Csqrt%7Bab%7D%3DAB%20%5Cquad%20%5Cquad%20%5B%5Cbecause%20O%27%20DAB%5C%3B%5C%3B%20%5Ctext%7Bis%20a%20rectangle.%7D%5D)
Hence, 
Answer:
B). $38,821
Step-by-step explanation:
By using several of the known mathematical formulas, and what is given to us at the very bottom (and top) of the answer, we can see that the correct answer is
$38,821
on e2020
Answer:
Infinite Solutions
Step-by-step explanation:
x + 2y = 10
6y = 3x - 30
To solve for x and y we use substitution method
Let's solve the first equation for x
x + 2y = 10
Subtract 2y on both sides
x = 10 - 2y
Now plug in x in second equation
6y = -3x + -30
6y = -3 (10-2y) - 30
6y = -30 + 6y - 30
6y = 6y
Both sides are the same, so both x and y have infinite solutions.