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boyakko [2]
3 years ago
12

I WILL GIVE BRAINLIEST PLZZ HELP!!!!!!!!!

Mathematics
2 answers:
klasskru [66]3 years ago
5 0

Answer:

D half a barrel an hour

Step-by-step explanation:

hope it helps

miskamm [114]3 years ago
5 0
It’s the last one.:)
You might be interested in
Help me pls pls pls :(
sveta [45]
740 square meters

Just find the areas of all the faces of the prism. And add then all up:

Area of rectangular base (bottom):
16 • 10= 160 square meters

Area of triangle facing front:
1/2 • 15 • 16= 120
Multiply 120 by 2 cause theres a same triangle facing back the prism: 120 • 2= 240

Area of rectangle facing right:
10 • 17= 170
Multiply 170 by 2 cause theres a same rectangle facing left the prism: 170 • 2= 340

Add them all up together:
160+ 240+340= 740

Comm.ent me if u have any questions

MARK ME BRAINLIEST TYSM! Say if my answer was wrong/right!
3 0
3 years ago
Read 2 more answers
two passenger train traveling in opposite directions meet and pass each other. Each train is 1/18 miles long and is traveling at
xz_007 [3.2K]

9514 1404 393

Answer:

  5 seconds

Step-by-step explanation:

Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...

  time = distance/speed

  time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s

That is, the rear part of each train will be at point A 5 seconds after the front part.

The rear parts will pass each other 5 seconds after the front parts meet.

6 0
3 years ago
Can someone plz answer my last question
Luda [366]
What was it?
math?
health?

7 0
3 years ago
Read 2 more answers
If the first equation is multiplied by 5, by what number would the second equation need to be multiplied to eliminate x by the a
Ratling [72]

Answer:

i am sorry but i do not no how to do this but if you type it in to the web browser you should gat an answer

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write the equation of the line perpendicular to y=5/6x+7/6 that passes through the point (-8,9) .
Bess [88]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{5}{6}}x+\cfrac{7}{6}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we can say that

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{5}{6}} ~\hfill \stackrel{reciprocal}{\cfrac{6}{5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{6}{5}}}

so we're really looking for the equation of a line with a slope of -6/5 and that passes through (-8 , 9)

(\stackrel{x_1}{-8}~,~\stackrel{y_1}{9})\qquad\qquad \stackrel{slope}{m}\implies -\cfrac{6}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{-\cfrac{6}{5}}(x-\stackrel{x_1}{(-8)})\implies y-9=-\cfrac{6}{5}(x+8) \\\\\\ y-9=-\cfrac{6}{5}x-\cfrac{48}{5}\implies y=-\cfrac{6}{5}x-\cfrac{48}{5}+9\implies y=-\cfrac{6}{5}x-\cfrac{3}{5}

7 0
2 years ago
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