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mario62 [17]
3 years ago
7

What shapes will appear in net for a rectangular prism that is not a cube? How many of the ships will there be?

Mathematics
1 answer:
Lyrx [107]3 years ago
6 0
There would be 6 shapes, and it would depend on what those shapes are since you wouldn't know the measurements.
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A number r is more than 0 or less than or equal to ‐8
Butoxors [25]

Answer

-8 \geq r > 0

Step-by-step explanation:

you know that r is less than or equal to -8, so you write that, and then you know that r is also greater than 0, so then you add that to it, and then you have the answer. r will be in the middle because it is the range of what are can be.

7 0
3 years ago
Jessica is walking home from a friend's house. After two minutes she is 0.8 miles from home. Eight minutes after leaving, she is
kolbaska11 [484]
6mph 6mph gotchu bro
4 0
3 years ago
Find the area of each figure
Anon25 [30]
Area of trapezoid = a + b/2 * h
a = 20, b = 9, h = 21/-16
20+9/2 * (21-16) = 29/2 * 5 = 72.5
The area of the trapezoid = 72.5 in^2

Area of the rectangle = l * w
l = 16, w = 20
16 * 20 = 320
The area of the rectangle: 320 in^2
7 0
3 years ago
For f(x) = 1/3x +5 <br><br> f(3) =
Mrrafil [7]

Answer:

f(3) = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 1/3x + 5

f(3) is x = 3

<u>Step 2: Evaluate</u>

  1. Substitute:                    f(3) = 1/3(3) + 5
  2. Multiply:                        f(3) = 1 + 5
  3. Add:                              f(3) = 6
3 0
3 years ago
WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!
Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: a^2-b^2=(a+b)(a-b)

Given  x^2-16=0

Rewrite 16 as 4²

Therefore, a^2=x^2 and b^2=4^2

\implies a = \sqrt{x^2}=x

\implies b=\sqrt{4^2} =4

\implies x^2-16^2=(x+4)(x-4)

\implies (x+4)(x-4)=0

\implies (x+4)=0 \implies x=-4

\implies (x-4)=0 \implies x=4

<u>Method 2</u>

Given equation:

x^2-16=0

Add 16 to both sides:

\implies x^2-16+16=0 + 16

\implies x^2=16

Square root both sides:

\implies \sqrt{x^2}=\sqrt{16}

\implies x=\pm4

Therefore, x = -4, x = 4

6 0
2 years ago
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