Answer:
a) No. It is not normal.
b) The probability that 700 randomly selected cars at this freeway entrance will carry more than 1075 people is 0.104
Step-by-step explanation:
<u>(a) Could the exact distribution of the count be Normal?</u>
The exact distribution of the number of people in each car entering a freeway at a suburban interchange is not normal. Because the count is <em>discrete </em>and <em>can assume values bigger or equal to one</em>.
<u>(b) The probability that 700 randomly selected cars at this freeway entrance will carry more than 1075 people.</u>
The probability we seek is the cars carrying people with mean more than 
That is P(z>z*) where z* is the z-score of 1.5357.
z* can be calculated using the equation:
z*=
where
- X is the mean value wee seek for its z-score (1.5357)
- M is the average count of people entering a freeway at a suburban interchange. (1.5)
- s is the standard deviation of the count (0.75)
- N is the sample size (700)
Thus z*=
≈ 1.26
We have P(z>1.26)=1-P(z≤1.26)= 1-0.896 = 0.104
Answer: x = -7
Step-by-step explanation: to do the problem -3x - 11 = 10, first separate the x from everything else, except the -3. To do this, you have to get rid of the 11, and since it is negative, you have to add it to both sides of the equation. This gets rid of the 11 on the left side, and adds 11 to the right side, making the right side equal 21. Last, divide -3 from both sides to get x on the left, and -7 on the right. This makes x = -7
So first thousandth is the third place backwards and the first one is already right and same with the second....