3 years ago

Find the ratio in which the line segment joining - 2 - 3 and 5 and 6 is divided by x– axis

Mathematics

1 answer:

nexus9112 [7]3 years ago

4 0

Answer:

x axis ?

Step-by-step explanation:

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Wittaler [7]

Answer:

$\frac{41}{3} < 14 < \sqrt{200}$

<u> $0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} }$ </u>

Step-by-step explanation:

$\sqrt{200} = 10 \sqrt{2} = 14.1 \\ 14 = 14 \\ \frac{41}{3} = 13.6$

So ;

$\frac{41}{3} < 14 < \sqrt{200} \\ 13.6 < 14 < 14.1$

$\frac{2}{3} = 0.66 \\ \sqrt{ \frac{9}{16} } = \frac{3}{4} = 0.75 \\ 0.6 = 0.6$

So ;

$0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } \\ 0.6 < 0.66 < 0.75$

I hope I helped you^_^

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(0,2) is your answer

Explanation

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Step-by-step explanation:

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Find the ratio in which the line segment joining - 2 - 3 and 5 and 6 is divided by x– axis​

Find the ratio in which the line segment joining - 2 - 3 and 5 and 6 is divided by x– axis