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givi [52]
3 years ago
10

Find the ratio in which the line segment joining - 2 - 3 and 5 and 6 is divided by x– axis​

Mathematics
1 answer:
nexus9112 [7]3 years ago
4 0

Answer:

x axis ?

Step-by-step explanation:

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8/f = 56/105 what is f?
svetlana [45]
8/15 = 56/105

This may be solved using proportion.
a/b = c/d
ad = bc   where cross products are equal.

a = 8
b = f
c  = 56
d = 105

ad = bc
8*105 = f*56
840 = 56f
840/56 = 56f/56
f = 15

56 ÷ 7 = 8
105 ÷ 7 = 15
6 0
3 years ago
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How do I write the number 17,497,403 well i know how to do it inside standard but my equation says “Write the number Seventeen m
MrRa [10]

Step-by-step explanation:

Standard form is of course 17,497,403.

Expanded form is:

10,000,000 + 7,000,000 + 400,000 + 90,000 + 7,000 + 400 + 3

7 0
3 years ago
I really need help with this please help best aswer gets brainliest
svet-max [94.6K]

Answer:

Relative frequency is 7.41% or 0.0741

Step-by-step explanation:

Given

The Attached Table

Required

Calculate the relative frequency of the class with lower limit 27

Relative Frequency is calculated by dividing individual frequency by the total frequency

Mathematically,

Relative\ Frequency = \frac{Individual\ Frequency}{Total\ Frequency}

The total frequency of the given data is 6+8+4+2+5+2

Total\ Frequency = 27

The class with lower limit 27 has a frequency of 2;

Hence;

Relative\ Frequency = \frac{Individual\ Frequency}{Total\ Frequency} becomes

Relative\ Frequency = \frac{2}{27}

Relative\ Frequency = 0.07407407407

Relative\ Frequency = 0.0741 (Approximated)

You may also leave your answer in percentage form

Relative\ Frequency = 0.0741 * 100\%

Relative\ Frequency = 7.41 \%

Hence, the relative frequency is 7.41% or 0.0741

7 0
3 years ago
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Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°
jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3  and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

                 =540°=180°

                 =360°.

Hence, the sum of all the external angles of a triangle is 360°.

5 0
3 years ago
Pls help ASAP ‼️ will give brainliest
vlada-n [284]

Answer: 2592

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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