Find the ratio in which the line segment joining - 2 - 3 and 5 and 6 is divided by x

svetlana [45]

8/15 = 56/105

This may be solved using proportion.
a/b = c/d
ad = bc where cross products are equal.

a = 8
b = f
c = 56
d = 105

ad = bc
8*105 = f*56
840 = 56f
840/56 = 56f/56
f = 15

56 ÷ 7 = 8
105 ÷ 7 = 15

6 0

3 years ago

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How do I write the number 17,497,403 well i know how to do it inside standard but my equation says “Write the number Seventeen m

MrRa [10]

Step-by-step explanation:

Standard form is of course 17,497,403.

Expanded form is:

10,000,000 + 7,000,000 + 400,000 + 90,000 + 7,000 + 400 + 3

7 0

3 years ago

I really need help with this please help best aswer gets brainliest

svet-max [94.6K]

Answer:

Relative frequency is 7.41% or 0.0741

Step-by-step explanation:

Given

The Attached Table

Required

Calculate the relative frequency of the class with lower limit 27

Relative Frequency is calculated by dividing individual frequency by the total frequency

Mathematically,

$Relative\ Frequency = \frac{Individual\ Frequency}{Total\ Frequency}$

The total frequency of the given data is 6+8+4+2+5+2

$Total\ Frequency = 27$

The class with lower limit 27 has a frequency of 2;

Hence;

$Relative\ Frequency = \frac{Individual\ Frequency}{Total\ Frequency}$ becomes

$Relative\ Frequency = \frac{2}{27}$

$Relative\ Frequency = 0.07407407407$

$Relative\ Frequency = 0.0741$ (Approximated)

You may also leave your answer in percentage form

$Relative\ Frequency = 0.0741 * 100\%$

$Relative\ Frequency = 7.41 \%$

Hence, the relative frequency is 7.41% or 0.0741

7 0

3 years ago

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Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°

jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1, ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3 and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

=540°=180°

=360°.

Hence, the sum of all the external angles of a triangle is 360°.

5 0

3 years ago

Pls help ASAP ‼️ will give brainliest

vlada-n [284]

Answer: 2592

Step-by-step explanation:

4 0

3 years ago

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Find the ratio in which the line segment joining - 2 - 3 and 5 and 6 is divided by x– axis​

Find the ratio in which the line segment joining - 2 - 3 and 5 and 6 is divided by x– axis