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Scrat [10]
4 years ago
10

During a race, Bernie ran 9 meters every 4 seconds, while Wendel ran 2 meters every second and got a 9-meter head start. If the

race was 70 meters long, did Bernie ever catch up with Wendel in the race?
Mathematics
1 answer:
Vsevolod [243]4 years ago
8 0
No, because Bernie had to run 9 meters 7.77777778 time (70/9) and each of those 9-meter sections took 4 seconds, so her time was 31.1111111 (7.77777778*4). While Wendel had to run 61 meters 70-his headstart (9 meters) (70-9). So he only had to run 30.5 blocks of 2 meters (61/2). And since they're only 1 second long, it's 30.5*1=30.5. The answer then is NO because (Bernie) 31.1111111 seconds > 30.5 seconds (Wendel).
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
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lawyer [7]

Answer:

Sum of the Roots = 37

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Step-by-step explanation:

Here, the given expression is  x^{2}  - 37x + 27 = 0

Now the general Quadratic Equation is of the form:

ax^{2}  + bx + c = 0

Here, Sum of the Roots = -(\frac{b}{a} )

and the Product of the Roots =  (\frac{c}{a} )

So, comparing the general equation with the given equation, we get:

a = 1, b = -37 and c = 27

So, Sum of the Roots = -(\frac{-37}{1} )  =  37

and the Product of the Roots =  (\frac{27}{1} ) = 27

6 0
3 years ago
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aliya0001 [1]

Answer:

The answer is 66.6346 round it to what ever place you need to.

Step-by-step explanation:

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