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Travka [436]
4 years ago
8

Please help ( 20 points )

Mathematics
1 answer:
VashaNatasha [74]4 years ago
7 0

Answer:

1+pi/2, 5/2, square root of 12-1, 2.25. Let me know if this is correct!


Step-by-step explanation:


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**Answers needed fast** Jason says his measurement is larger than Marco’s measurement because
tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

Jason is not correct because 0.819 is not larger than 0.85. Marco's number is larger.

5 0
3 years ago
What are the vertex and x-intercepts of the graph of y=x2-2x-24
valentina_108 [34]

Answer:

Vertex (1,-25), Intercepts at (6,0) and (-4,0)

Step-by-step explanation:

Axis of symmetry = -b/2a = -(-2)/2(1) = 2/2 = 1 so x=1 is the equation of line

Plug x=1 into equation y=1-2-24=-25

factor for x-intercepts:  (x-6)(x+4)

set them equal to zero: x-6=0 so x=6   x+4=0 so x= - 4


3 0
4 years ago
Read 2 more answers
The Quadratic equation y=0.5(x-1)(x-n) has an x - intercept at (1,0) and a vertex at (-2,4.5). what is the value of n A -5 B -2
andre [41]

Step-by-step explanation:

the point being that a quadratic equation has 2 x-intercepts (or solutions of x for y = 0).

the advantage of this nice form the equation is written in is, that we see immediately both conditions, when y can be 0 : one of the bracket expressions must be 0.

so, the point (1, 0) covers (x-1).

we get the solution for (x-n), when we consider that such a quadratic function is simply a parabola and is symmetric around its vertex point.

the x value of the vertex (-2) tells us, that it is 3 units on the left side of the (1, 0) x-intercept point.

due to the symmetry of the curve the second x-intercept point must be even further to the left with additional 3 units distance in x direction.

so, -2 - 3 = -5

and A is the correct answer option.

8 0
3 years ago
In this question, i is a unit vector due east and j is a unit vector due north. A cyclist rides at a speed of 4 m/s on a bearing
d1i1m1o1n [39]

<u>Answer:</u>

a) 1.04i + 3.86j

b) magnitude = 8; bearing = 302.7°

<u>Step-by-step explanation:</u>

a)

The  first diagram represents the velocity vector of the cyclist.

To express this vector in the form xi + yj, we have to find the components of the vector in the horizontal (i) and vertical (j) directions.

If we consider the horizontal component of the vector to be x, and the vertical component to be y, then:

• horizontal component ⇒ sin (15^{\circ}) = \frac{x}{4}

                                       ⇒ x = 4\space\ sin(15^{\circ})

                                       ⇒ x \approx \bf 1.04

• vertical component ⇒ cos(15^{\circ}) = \frac{y}{4}

                                   ⇒ y = 4 \space\ cos(15^{\circ})

                                   ⇒ y \approx \bf 3.86

Now that we have the values of both the horizontal and vertical component, we can write the vector in the form of xi + yj:

vector ⇒ 1.04i + 3.86j

b)

The second diagram shows the first vector (red), the second vector (blue), and the resultant vector <em>v</em> (black). The dashed lines represent the components of the respective vectors.

To add two vectors given their magnitudes and direction, we have to add their components.

In order to find the horizontal and vertical components of the given vectors, we can use a method similar to that used above, so that:

○ For the first vector (magnitude 6):

• horizontal component ⇒ x = 6 \space\ sin (60^{\circ})

                                       ⇒ \bf 5.2

• vertical component ⇒ y = 6 \space\ cos(60^{\circ})

                                   ⇒ y = \bf 3

○ For the second vector (magnitude 2):

• horizontal component ⇒ x = 2 \space\ cos (40^{\circ})

                                       ⇒ \bf 1.5

• vertical component ⇒ y = 2 \space\ sin(40^{\circ})

                                   ⇒ \bf 1.3

Now we can add the respective components together:

v = 5.2i + 3j  +  1.5i + 1.3j

 ⇒ (5.2 + 1.5)i + (3 + 1.3)j

 ⇒  6.7i + 4.3j

∴ Magnitude of v ⇒ |v| = \sqrt{(6.7)^2 + (4.3)^2}

                             ⇒ |v| \approx \bf 8

To find the bearing of <em>v</em>, we have to first calculate the angle marked \alpha:

tan \alpha = \frac{4.3}{6.7}

⇒ \alpha = tan^{-1}(\frac{4.3}{6.7})

⇒ \alpha = \bf 32.7^{\circ}

∴ Bearing = 270° + 32.7°

                = 302.7°

8 0
2 years ago
18 3/8f = -29 4/7 please help
KatRina [158]

Answer:

f=-552 /343 or 5=1 and 209/343

Step-by-step explanation:

4 0
3 years ago
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