Question

Y= x+14 , x+ 2y= 36, find x and y and show solution pls

Answer 1

Step-by-step explanation:

given

$y = x + 14 \\ y - x = 14 \\ - x + y = 14$

as equation 1

and

$x + 2y = 36$

as equation 2.

We will now use elimination method to solve simultaneous equations.

We will use equation 1 + equation 2 to eliminate x and solve for y.

$- x + x + y + 2y = 14 + 36 \\ 0 + 3y = 50 \\ 3y = 50 \\ y = 50 \div 3 \\ = \frac{50}{3} \: or \: 16 \frac{2}{3}$

Now substitute y into equation 1.

$y = x + 14 \\ x + 14 = y \\ x = y - 14 \\ x = 16\frac{2}{3} - 14 \\ = 2 \frac{2}{3}$

Answer 2

Answer:

Solve the equation for x.

The simplified system is the arbitrary solution of the original system of equations.

Y=x+14

y=18−x2

Reorder 18

and −x2.

y=−x2+18

Y=x+14

Solve the equation for Y.

Y=−2y+50

x=36−2y

Reorder 36

and −2y.

x=−2y+36

Y=−2y+50

Step-by-step explanation: