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Lynna [10]
3 years ago
7

Helppp outt plss....​

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0
<h3>Answers:  x = 30 and y = 150</h3>

============================================================

Explanation:

For any cyclic quadrilateral (aka inscribed quadrilateral), the opposite angles are always supplementary.

One pair of such angles is A and C

A+C = 180

x+y = 180 is one equation to form

The other pair of supplementary angles is B and D

B+D = 180

y-45+2x+15 = 180

2x+y-30 = 180

2x+y = 180+30

2x+y = 210 is the other equation to form

--------------

So the system of equations we have is

\begin{cases}x+y = 180\\2x+y = 210\end{cases}

Both equations involve 'y', with the same coefficient, so we can subtract straight down to eliminate this variable.

  • The x terms subtract to x-2x = -x
  • The y terms subtract to y-y = 0y = 0, so the y terms go away
  • The right hand sides subtract to 180-210 = -30

We end up with -x = -30 which solves to x = 30

--------------

Once we know x, we can determine y by plugging it into any equation involving x,y and solving for y

Let's say we picked on the first equation

x+y = 180

30+y = 180

y = 180-30

y = 150

Or we could pick on the second equation

2x+y = 210

2(30) + y = 210

60+y = 210

y = 210-60

y = 150

Only one equation is needed. However, doing both like this shows that we get the same y value, and it helps confirm the answers.

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Write an equation of a line (in standard form) that has the same slope as the line 3x-5y=7 and the same y-intercept as the line
Vanyuwa [196]

Answer:

3x-5y=-20

Step-by-step explanation:

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have two standard form equations which we will get a slope and a y-intercept from. We will convert each to slope intercept form to get the information. We will then write a new slope-intercept equation and convert to standard form.

3x-5y=7 has the same slope as the line. Let's convert.

3x-5y=7\\3x-3x-5y=7-3x\\-5y=7-3x\\\frac{-5y}{-5}=\frac{7-3x}{-5} \\

y=\frac{3}{5}x -\frac{7}{5}

The slope is m=\frac{3}{5}.

2y-9x=8 has the same y-intercept as the line. Let's convert.

2y-9x=8\\2y-9x+9x=8+9x\\2y=8+9x\\\frac{2y}{2}=\frac{8+9x}{2}

y=\frac{8}{2}+\frac{9x}{2}  \\y=4+\frac{9}{2}x

The y-intercept is 4.

We take m=\frac{3}{5} and b=4 and substitute into y=mx+b.

y=\frac{3}{5}x+4

We now convert to standard form.

-\frac{3}{5}x+y=\frac{3}{5}x-\frac{3}{5}x+4\\-\frac{3}{5}x+y=4

For standard form we need the coefficients of x and y to be not zero or fractions. We need integers but the coefficient of x cannot be negative. So we multiply the entire equation by -5 to clear the denominators.

-5(-\frac{3}{5}x+y=4)\\3x-5y=-20



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3 years ago
Mr. Gonzales has only $55.00 to spend at a clothing store. He wants to buy a shirt that costs $30, including tax, and some brace
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55-30-x=0. ?

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