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Snowcat [4.5K]
3 years ago
6

Read the question and type your response in the box provided. Your response will be saved automatically.

Mathematics
2 answers:
larisa [96]3 years ago
4 0

Answer:

512

Step-by-step explanation:

8 x 8 x 8 = 512

Oliga [24]3 years ago
4 0

Answer:

512

Step-by-step explanation:

Given

8 = \sqrt[3]{?}

To find the value inside the cube root, use the inverse operation.

The inverse of cube root is cube, thus

? = 8³ = 8 × 8 × 8 = 64 × 8 = 512

You might be interested in
crater Lake in Oregon in shaped like a circle with a diameter of about 5.5 miles. What is the area of the surface of crater lake
N76 [4]

Answer:

Given the statement: Crater Lake in Oregon in shaped like a circle with a diameter of about 5.5 miles.

Area of circle is given by:

A = \pi \frac{d^2}{4}

where

A represents the area of a circle

d represents the diameter of a circle.

then;

It is given that Surface of Crater lake is shaped like a circle.

Substitute the given values, we have;

Area of a circle = \pi \frac{(5.5)^2}{4}

= 3.14 \times \frac{30.25}{4} =3.14 \times 7.5625 = 23.74625 square miles

therefore, the area of a surface of a crater lake is, 23.74625 square miles.

3 0
3 years ago
Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).
Firdavs [7]

Answer:

A) Particular solution:

2x+\frac{1}{2}e^{-x}-\frac{8}{5}

B) Homogeneous solution:

y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))

C) The most general solution is

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

Step-by-step explanation:

Given non homogeneous ODE is

y''+4y'+5y=10x+e^{-x}---(1)

To find homogeneous solution:

D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)

To find particular solution:

y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\

Substituting y_{p},y'_{p},y''_{p} in (1)

y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\

Equating the coefficients

5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\

The general solution is

y=y_{h}+y_{p}

from (2) ad (3)

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

6 0
3 years ago
Choose the more precise measurement. A) 32.5 lb B) 28.35 lb *​
s2008m [1.1K]

Answer:

B is the answer

Step-by-step explanation:

I hope it will help u (◕ᴗ◕✿)

8 0
3 years ago
Alicia answered 20 out of 25 problems correctly on a test. What percent did she get correct?
DedPeter [7]
80% of the problems correct.
3 0
3 years ago
Read 2 more answers
1
NikAS [45]

9514 1404 393

Answer:

  1.0 N

Step-by-step explanation:

When the length increases by the factor 120/80 = 3/2, the force required is multiplied by the inverse of this: 2/3.

The required force is ...

  (2/3)(1.5 N) = 1.0 N

5 0
3 years ago
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