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Ilia_Sergeevich [38]
4 years ago
13

In right triangle ABC, AB = 6, BC =12, and m

Mathematics
2 answers:
pishuonlain [190]4 years ago
6 0

Answer:


Step-by-step explanation:

The way the triangle is laid out, BC is the hypotenuse, and AB is the side opposite <C. You hare given that the Sin<C = 1/2

If Sin<C = 1/2 then C = 30 degrees. It is part of the unit circle.

The tan (<30 degrees) = 1/sqrt(3)  from the unit circle.

The cotangent of 30degrees = 1/tan(30) = sqrt(3)

cot(30) = sqrt(3) = 1.7321

tigry1 [53]4 years ago
6 0
Calculator screen; bottom-right is the answer to top-left.
Cot(30) = sqrt(3). The correct answer is option A.

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From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of
Umnica [9.8K]

\large\bold{{Question :}}

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of the circle.

\large\bold\red{\underline{Solution :-}}

Here, O is the center of the circle.

<u>⟼</u><u> </u><u>Given</u><u> </u><u>:</u>

  • OQ = 25 cm
  • PQ = 24 cm

<u>⟼</u><u> </u><u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u> </u> We have to find the radius OP.

Since QP is tangent, OP perpendicular to QP.

(Since, Tangent is Perpendicular to Radius ⠀⠀⠀⠀⠀⠀⠀at the point of contact)

So, ∠OPQ=90°

<u>⟼</u><u> </u><u>By</u><u> </u><u>Applying</u><u> </u><u>Pythagoras</u><u> </u><u>Theorem</u><u> </u><u>:</u>

OP² + RQ² = OQ²

OP² + (24)² = (25)²

OP² = 625 - 576

OP² = 49

OP = √49

<u>OP</u><u> </u><u>=</u><u> </u><u>7</u><u> </u><u>cm</u>

<u>Hence</u><u>,</u><u> </u><u>The</u><u> </u><u>Radius</u><u> </u><u>is</u><u> </u><u>7</u><u> </u><u>cm</u>

⠀⠀

⠀

<h3>-MissAbhi</h3>

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