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3 years ago

I need help please!!!

Mathematics

1 answer:

emmasim [6.3K]3 years ago

5 0

Answer:

Step-by-step explanation:

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Write in point-slope form an equation of the line that passes through the point (3,0) with slope 23.

Radda [10]

Answer:

$y-0=23(x-3)$

Step-by-step explanation:

Point-slope form: $y-y_1=m(x-x_1)$ when the given point is $(x_1,y_1)$ and $m$ is the slope

$y-y_1=m(x-x_1)$

Plug in the point

$y-0=m(x-3)$

Plug in the slope

$y-0=23(x-3)$

I hope this helps!

5 0

2 years ago

In a classroom, there are 13 scholars. Each scholar has a total of $1.75 in each pocket. If every scholar has a total of two poc

mylen [45]

13 x 1.75 = 22.75

take 22.75 and multiply by 2

you should get 45.50

5 0

3 years ago

Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript one-fourth x?

Nat2105 [25]

<h3>Answer: Choice C</h3>

RootIndex 12 StartRoot 8 EndRoot Superscript x

12th root of 8^x = (12th root of 8)^x

$\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}$

=========================================

Explanation:

The general rule is

$\sqrt[n]{x} = x^{1/n}$

so any nth root is the same as having a fractional exponent 1/n.

Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)

$\sqrt[3]{8} = 8^{1/3}$

-----

Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so

(1/3)*(1/4)x = (1/12)x

In other words,

$\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/3)*(1/4)x}$

$\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/12)x}$

-----

From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this

$8^{(1/12)x} = \sqrt[12]{8^{x}}$

$8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}$

4 0

3 years ago

Read 2 more answers

I need help please???

goblinko [34]

option 4 .x<11 is the correct answer

4 0

3 years ago

Solve logarithmic equation

Maksim231197 [3]

Answer:

x=6

Step-by-step explanation:

ln 1=0

x-5=1

x=6

4 0

2 years ago

Read 2 more answers