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Sliva [168]
3 years ago
10

Figure RST on the graph is reflected over the y-axis creating figure R’S’T’. Figure R’S’T’ is translated down 2 units and left 1

unit creating R’’S’’T’’. On a coordinate plane, triangle R S T has points (1, 1), (2, 3), (1, 4). Triangle R prime S prime T prime has points (negative 1, 1), (negative 2, 3), (negative 1, 4). Triangle R double-prime S double-prime T double-prime has points (negative 2, negative 1), (negative 3, 1), (negative 2, 2). Tyler knows that RST Is congruent to R’S’T’ because reflections produce congruent figures. He also knows that R’S’T’ Is congruent to R’’S’’T’’ because translations produce congruent figures. What can Tyler determine based on these two statements? Check all that apply. RST Is congruent to R’’S’’T’’ RS Is congruent to ST Is congruent to TR Angle R is congruent to angle S is congruent to angle T Angle R is congruent to angle R prime is congruent to angle R double-prime TS Is congruent to T’S’ Is congruent to T’’S’’
Mathematics
2 answers:
oee [108]3 years ago
4 0

For those who like the short answer, it is A and D

Crazy boy [7]3 years ago
3 0

Answer:

RST Is congruent to R’’S’’T’’

Angle R is congruent to angle R prime is congruent to angle R double-prime

TS Is congruent to T’S’ Is congruent to T’’S’’

Step-by-step explanation:

we know that

A reflection and a translation are rigid transformation that produce congruent figures

If two or more figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

Triangles RST, R'S'T and R''S''T'' are congruent

That means

Corresponding sides

RS≅R'S'≅R''S''

ST≅S'T'≅S''T''

RT≅R'T'≅R''T''

Corresponding angles

∠R≅∠R'≅∠R''

∠S≅∠S'≅∠S''

∠T≅∠T'≅∠T''

therefore

RST Is congruent to R’’S’’T’’

Angle R is congruent to angle R prime is congruent to angle R double-prime

TS Is congruent to T’S’ Is congruent to T’’S’’

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34/3/4 = 45.3333333333

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7 0
3 years ago
How do i solve this quadratic equation x²+6x+c
Anuta_ua [19.1K]

recall in a perfect square trinomial, the middle term is the tale-tell guy, we know the middle term is the product of 2 and the two other guys without the exponent, so in this case 6x = 2*√x² * √c.


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4 years ago
Find the arc length and area of a sector with radius R =60 inches and central angle equals 30° round your answer to the nearest
Black_prince [1.1K]

Answer:

(a)31.42 inches

(b)942.48 Square Inches

Step-by-step explanation:

Given a sector of a circle with the following dimensions:

Radius of the circle =60 inches

Central Angle of the sector =30°

(a)Arc Length

Arc Length =\dfrac{\theta}{360^\circ}X2\pi r

=\dfrac{30}{360^\circ}X2*60*\pi\\\\=10\pi\\\\=31.42$ Inches (correct to the nearest hundredth)

(b)Area of the sector

Area of the sector =\dfrac{\theta}{360^\circ}X\pi r^2

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3 0
4 years ago
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3 0
3 years ago
Solve the right angle trig problem.
Lisa [10]

Answer:

x = 40.7057°

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Trigonometry</u>

  • [Right Triangle Only] sin∅ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

We have a right triangle. We can use trig to find the angle.

<u>Step 2: Identify Variables</u>

Angle = <em>x</em>

Opposite = 15

Hypotenuse = 23

<u>Step 3: Find Angle </u><em><u>x</u></em>

  1. Substitute:                    sinx° = 15/23
  2. Inverse:                         x° = sin⁻¹(15/23)
  3. Evaluate:                       x = 40.7057°
6 0
3 years ago
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