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3 years ago

PLZ PLZ PLZ HELPPPP

Mathematics

1 answer:

Andrews [41]3 years ago

5 0

Answer:

LCD is 6

first choice

Step-by-step explanation:

least common denominator of 2 and 3 is 6

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3/8 is 4 & 3/5 % of what number? (Round to the nearest hundredth.)

Harman [31]

Answer:

n = 8.15

Step-by-step explanation:

3/8 is 4 & 3/5 % of what number?

Rewrite this as: 3/8 is (4 3/5)% of what number?

Convert 4 3/5% into a decimal: 0.046

Then write out and solve the equation 3/8 = 0.046n, where n is the unknown number.

Dividing both sides by 0.046, we get n = 8.15

4 0

3 years ago

An athlete took forward and backward steps of equal distance to warm up before his race. After taking 10 steps total, he was bac

snow_tiger [21]

If he took 5 steps forward and then 5 steps backwards he would be at his starting position

8 0

3 years ago

Annie works as both a carpenter and a blacksmith. Last week she worked 12 hours as a carpenter and 20 hours as a blacksmith and

Minchanka [31]

Answer:Let x = pay per hour as a carpenter and y = pay per hour as a blacksmith

Last week she worked 12 hours as a carpenter

earning 12x dollars

and 20 hours as a blacksmith

earning 20y dollars

and earned a total of $860

and those two things add up to 860.

Do the same with the other sentence, giving you a second equation.

Step-by-step explanation:

6 0

3 years ago

What is 5x^2+11x+2 factored

Alina [70]

Answer:

(x+2) (5x)

Step-by-step explanation:

the way I factor is the products of a*c added together equals b. so the products if (5*2) 10 equals 11. so 10 and 1 are the 2 products that add into 11. Now we put that into the equation. 5x^2+10x+1x+2 now take the two haves until you can't factor them any more 5x(x+2) (x+2). now take the repeated factor and outside factors to get (5x) and (x+2)

4 0

3 years ago

1) find the equation of the line parallel to

In-s [12.5K]

Answer:

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

Solution:

1) find the equation of the line parallel to x-5y=6 and through (4,-2).

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

4 0

3 years ago