A regular triangular pyramid is a solid figure with r surfaces
- 3 lateral surfaces and one base surface
- the four surfaces are congruent triangles, which is to say that all triangular surfaces have the same base and the same slant heght
- the area of each surface is [1/2] base * slant height.
Then, a change that double the area is any that keep one of the dimensiones and double the other.
So the answer is: double each side, b, of the base triangle while keeping the slant height, l, tha same.
You can also double the slant height, l, while keeping the base triangle, but then the height,h, of the pyramid will increase, by a factor which is not 2.
$17.40
I'm not 100% sure on this answer, but I don't think anyone else will be answering.
Answer:
![\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x} = \frac{x - 6}{4*x}](https://tex.z-dn.net/?f=%5Cfrac%7B2%2Ax%20-%202%7D%7B2%2Ax%7D%20%20-%20%5Cfrac%7B3%2Ax%20%2B%202%7D%7B4%2Ax%7D%20%3D%20%5Cfrac%7Bx%20-%206%7D%7B4%2Ax%7D)
Step-by-step explanation:
We have the expression:
![\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x}](https://tex.z-dn.net/?f=%5Cfrac%7B2%2Ax%20-%202%7D%7B2%2Ax%7D%20%20-%20%5Cfrac%7B3%2Ax%20%2B%202%7D%7B4%2Ax%7D)
The first thing we want to do, is to have the same denominator in both equations, then we need to multiply the first term by (2/2), so the denominator becomes 4*x
We will get:
![(\frac{2}{2} )\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x} = \frac{4*x - 4}{4*x} - \frac{3*x + 2}{4*x}](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B2%7D%20%29%5Cfrac%7B2%2Ax%20-%202%7D%7B2%2Ax%7D%20%20-%20%5Cfrac%7B3%2Ax%20%2B%202%7D%7B4%2Ax%7D%20%3D%20%5Cfrac%7B4%2Ax%20-%204%7D%7B4%2Ax%7D%20%20-%20%5Cfrac%7B3%2Ax%20%2B%202%7D%7B4%2Ax%7D)
Now we can directly add the terms to get:
![\frac{4*x - 4}{4*x} - \frac{3*x + 2}{4*x} = \frac{4*x - 4 - 3*x - 2}{4*x} = \frac{x - 6}{4*x}](https://tex.z-dn.net/?f=%5Cfrac%7B4%2Ax%20-%204%7D%7B4%2Ax%7D%20%20-%20%5Cfrac%7B3%2Ax%20%2B%202%7D%7B4%2Ax%7D%20%3D%20%5Cfrac%7B4%2Ax%20-%204%20-%203%2Ax%20-%202%7D%7B4%2Ax%7D%20%20%3D%20%5Cfrac%7Bx%20-%206%7D%7B4%2Ax%7D)
We can't simplify this anymore
Let the two numbers be x and y with x being the greater number.
Given,
x = 7 + y
Also given,
x + y = 39
Substituting the value of x from above,
7 + y + y = 39
7 + 2y = 39
2y = 39 - 7
2y = 32
y =
![\frac{32}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B32%7D%7B2%7D%20)
y = 16
x = 7 + y
x = 7 + 16
x = 23
Hence, the two numbers are 23 and 16.