Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
a15 = 35
Step-by-step explanation:
Given:
a3 = 11
a6 = 17
Find:
a15 = ?
Computation:
a3 = 11 ⇒ a+ 2d = 11..........Eq1
a6 = 17 ⇒ a + 5d = 17...............Eq2
From Eq2 - Eq1
⇒ 3d = 6
⇒ d = 2
And a = 7
So,
⇒ a15 = a + 14d
⇒ a15 = 7 + 14 (2)
⇒ a15 = 7 + 28
⇒ a15 = 35
Isosceles Triangle(two sides equal, two angles equal)1 Line of Symmetry.
Answer:
Step-by-step explanation:
Its 80 ounces
Actually, this graph has two asymptotes: a vertical one and a horiz. one.
Note that we cannot divide by zero. Thus, x = 0 is the vertical asymptote.
Note that as x continues to grow, y tends towards zero. Thus, y = 0 is the horiz. asy.
