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3 years ago

In a box of chocolates, 1/5 of the chocolates contain nuts.

Mathematics

1 answer:

liubo4ka [24]3 years ago

6 0

Answer:

1:4

Step-by-step explanation:

chocolates that contain nuts = 1/5

chocolates hat do not have nuts = 4/5

ratio = 1:4

I hope im rght! i

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Simplify the expression so there is only one positive power for each base 2.7^-3 * 3.8^2 *2.7^4 * 3.8^3

Firdavs [7]

$2.7^{-3}\cdot3.8^2\cdot2.7^4\cdot3.8^3\\\\=(2.7^{-3}\cdot2.7^4)\cdot(3.8^2\cdot3.8^3)\qquad|\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2.7^{-3+4}\cdot3.8^{2+3}\\\\=2.7^1\cdot3.8^5$

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Which of the following is a quadratic equation whose roots are 3 and -1?

scZoUnD [109]

Answer:
(x-3)(x+1)
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It says to solve for x but I don’t know how to do it

elena-14-01-66 [18.8K]

Answer:

0 & 3

Step-by-step explanation:

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4 years ago

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HELP ME PLEASE REAL ANSWERS ONLY

asambeis [7]

Answer: x=4, x=-5

Step-by-step explanation:

$\frac{x}{x-4}-\frac{4}{x+5}=\frac{36}{x^2+x-20}$

Multiply everything by the LCM = (x-4)(x+5):

$\frac{x}{x-4}\left(x-4\right)\left(x+5\right)-\frac{4}{x+5}\left(x-4\right)\left(x+5\right)=\frac{36}{x^2+x-20}\left(x-4\right)\left(x+5\right)$

$\frac{x\left(x-4\right)\left(x+5\right)}{x-4} -\frac{4\left(x-4\right)\left(x+5\right)}{x+5} =\frac{36\left(x-4\right)\left(x+5\right)}{\left(x-4\right)\left(x+5\right)}$

Simplify by cancelling out same terms: in the numerators and denominators:

$x\left(x+5\right)-4\left(x-4\right)=36$

$x^2+x-20=0$

(x+5)(x-4) = 0

The solution to the quadratic equation is x=4, x=-5

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2 years ago