Find the stationary points.
<em>f(x)</em> = <em>x</em> + 16/<em>x</em>
<em>f '(x)</em> = 1 - 16/<em>x</em> ²
Solve <em>f</em> <em>'(x)</em> = 0.
1 - 16/<em>x</em> ² = 0 → <em>x</em> ² = 16 → (<em>x</em> - 4) (<em>x</em> + 4) = 0
→ <em>x</em> = -4, <em>x</em> = 4
Check the value of <em>f</em> at the stationary points. <em>x</em> = -4 is not in the provided domain so we can omit it.
<em>f</em> (4) = 8
Check the value of <em>f</em> at the boundary of the domain.
<em>f</em> (0.2) = 401/5 = 80.2
<em>f</em> (16) = 17
Then over [0.2, 16], we have max(<em>f</em> ) = 401/5 and min(<em>f</em> ) = 8.
Answer:
I'm confused
Step-by-step explanation:
What am I suposed to do?
Answer:
The probability that the new baby just born is a boy is 0.6
Step-by-step explanation:
- B=Event where the nurse picked up a boy
- G=Event where the nurse picked up a girl
Applying Bayes's Theorem:
P(A|B)=P(A) P(B|A) / [ P(A) P(B|A)+ P(C) P(B|C) ]
Where:
- P(A|B)=probability that the new baby just born is a boy given that the nurse picked up a boy.
- P(A)=Probability that the woman had a boy= 1/2
- P(C)=Probability that the woman had a girl=1/2
The probability for P(A) and P(C) is 1/2 becuase there are only two options. Girl or Boy
n= number of girls born
3+n= Total number of children in the nursery
Then,
P(A|B)=
P(A|B)=3/5
P(A|B)=0.6
FOLLOW ME FOR CLEARING YOUR NEXT DOUBT
Answer:
yes i do believe so
Step-by-step explanation: