Answer:
P=3/4
Step-by-step explanation:
There are 3 possibilities for not purple. (pink, blue, green)
3/4
We know from Pythagoras' Theorem, a right angle triangle can be identified by the relationship:

Thus, we know if the side lengths of the triangle in question abide by this relation, the triangle is right.
First, we must find the greatest side length.
We know, using the distance formula.



From this, we know that:

Therefore, GB would be the hypotenuse of the triangle.
Now we substitute the values for the two shorter lengths and the greater length into the pythagorean theorem:



Therefore, this triangle is a right angled triangle
Answer:
Impossible, not enough to answer the question
Step-by-step explanation:
As you can see because there is no number or variable past the equal sign it is simply an expression, please correct me if I am wrong but even if the other side was 0, I doubt a teacher would give this problem with decimals, but it may just be me.
Answer: dude you can do this yourself.
Step-by-step explanation:
toss coins ;-;