<span>He has failed to consider the number 0, which is a whole number but not a natural number.</span>
Given :
a-b = c-d ...1)
b = d-1 ...2)
c = 6
To Prove :
a = 5
Solution :
Adding equation 1 and 2, we get :
(a-b) + (b) = (c-d) + (d-1)
a = c -1 ...3)
Putting given value of c = 6 in above equation, we get :
a = 6 - 1
a = 5
Hence, proved.
Answer:
domain= all real numbers
Range= y>=0
Step-by-step explanation:
You’re asking how many times does 2/3 fit into 12. This needs to be set up as 12 divided by 2/3.
Using the KFC rule, this is the same as 12 * 3/2
Does that help?
Answer:
1/3 or 0.3
Step-by-step explanation:
5/8 x 4/5 x 2/3 =
1/3 or 0.3
