Question

The seats at a local baseball stadium are arranged so that each row has five more seats than the row below it. If there are four seats in the first row, how many total seats are in the first 24 rows?

Answer 1

Answer:

Thus the last row has 119 seats.

The total number of seats in 24 rows = 1476

Step-by-step explanation:

The number of seats in each row make an arithmetic series. We will use arithmetic equation to find the number of seats in last row:

An = a1+ (n-1)d

An = 4+(24-1)5  

An = 4 + (23)(5)  

An = 4 + 115  

An = 119

Thus the last row has 119 seats.

Now to find the sum of seats we will apply the formula:

Sn = n(a1 + an)/2

Sn = 24(4+119)/2  

Sn = 24(123) /2  

Sn = 1476 .....

The total number of seats in 24 rows = 1476....

Answer 2

Answer:

1476 seats

Step-by-step explanation:

We are given that each row in a baseball stadium has five more seats than the row below it. Given that there are four seats in the first row, we are to find the total number of seats in the first 24 rows.

For this, we can use arithmetic sequence:

$a_n = a_1+ (n-1)d$

$a_n = 4+(24-1)5$

$a_n=119$

Now that we know the number of seats in the last row, we will plug the value to find total seats in first 24 rows:

$S_n=\frac{24(4+119)}{2}$

$S_n=1476$

Therefore, there are 1476 seats in the first 24 rows.