Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC= 
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
The answer is to the equation is b
To get the answer to this equation you first cancel out the 6! ;)
(x^2-1)(6x-1) / (x+1)
Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1
(x^2-1^2)(6x-1) / (x+1)
Then use the difference of squares!
(x+1)(x-1)(6x-1) / (x+1)
LASTLY cancel "x+1" !
so ur answer is (x-1) (6x-1)
That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)
YW!!! ;)
Answer:
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Step-by-step explanation:njjjn
Answer:
Percentage increases and decreases, are found by setting the problem up proportionally.
You are trying to find what percentage of 17.37 is 8.30 first.
so What %/100 = 8.30/17.37
Now define a variable:
Let x = What%
x/100 = 8.30/17.37
17.37x = 830
x = 830/17.37
x ≈ 47.78
8.30 is approximately 47.78% of 17.37, so the percentage decrease is 100% - 47.78% = 52.22%
The percentage decrease is approximately 52.22%
