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3 years ago

Determine if the sequence below is arithmetic or geometric and determine the

Mathematics

1 answer:

KengaRu [80]3 years ago

7 0

Answer:

Arithmetic sequence; common difference is 8.

Step-by-step explanation:

An arithmetic sequence increases or decreases by a fixed amount from term-to-term.

10 - 2 = 8

18 - 10 = 8

The next term will be 18 + 8 = 26, and so on.

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Two forces, one of 45 pounds and the other 50 pounds, act on the same object. The angle between the forces is 33°. Find the magn

bearhunter [10]

Answer:

The magnitude of the resultant force is: 27.40 pounds

Step-by-step explanation:

Given

$F_1 = 45$

$F_2 = 50$

$\theta = 33$

Required

The magnitude of the resultant vector

To do this, we apply cosine formula

$R^2 = F_1^2 + F_2^2 - 2 * F_1 * F_2 * \cos(\theta)$

This gives:

$R^2 = 45^2 + 50^2 - 2 * 45 * 50 * \cos(33)$

$R^2 = 2025+ 2500 - 4500* 0.8387$

$R^2 = 2025+ 2500 - 3774.15$

$R^2 = 750.85$

Take square roots of both sides

$R = \sqrt{750.85\\$

$R = 27.40$

7 0

3 years ago

What’s the area and the perimeter and of the triangle?

asambeis [7]

Answer:

Area = 3.3998

Perimeter = 2.9

Step-by-step explanation:

A method for calculating the area of a triangle when you know the lengths of all three sides.

Let a,b,c be the lengths of the sides of a triangle. The area is given by:

Area = √ p ( p − a ) ( p − b ) ( p − c )

where p is half the perimeter, or

a + b + c / 2

p = 1.7 + 1.7 + 2.4 / 2 = 5.8 / 2 = 2.9

a = Area = 3.3998

Heron was one of the great mathematicians of antiquity and came up with this formula sometime in the first century BC, although it may have been known earlier. He also extended it to the area of quadrilaterals and higher-order polygons.

8 0

2 years ago

The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv

Gelneren [198K]

Answer:

$v_2 \approx 1.12246\ m.s^{-1}$

$v_{10}\approx 1.4678\ m.s^{-1}$

$v_{100}\approx 1.4678\ m.s^{-1}$

Step-by-step explanation:

Mass of particles that a river can transport, $m\propto\ v^6$

where:

v = velocity of river flow

When $v=1\ m.s$

then the mass transported, $m \propto 1^6$

When mass is twice:

$v=\sqrt[6]{2}$

$v_2 \approx 1.12246\ m.s^{-1}$

When mass is 10 times:

$v=\sqrt[6]{10}$

$v_{10}\approx 1.4678\ m.s^{-1}$

When mass is 100 times:

$v=\sqrt[6]{100}$

$v_{100}\approx 1.4678\ m.s^{-1}$

7 0

3 years ago

I need help please thanks

nikdorinn [45]

Answer:

pick all 3 of the bottom row

5 0

3 years ago

Read 2 more answers

Can you help me? What is: -3x=15 M-8= -5

Gre4nikov [31]

Answer:

m=3,x=-5 solveing the sysytem of equations

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers