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nika2105 [10]
3 years ago
9

The answer to this problem

Mathematics
1 answer:
IrinaK [193]3 years ago
4 0

Answer:

Which question are you needing help with?

Step-by-step explanation:

You might be interested in
P=21+2w; if p=18 when l=5, find w
jolli1 [7]

Answer:

if im not mistaken.. i would say its -3.5 or -7/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If the product of 2 identical numbers is 441 find one of the numbers <br>full process please ​
son4ous [18]

Answer:

21

Step-by-step explanation:

let n be the identical number, then

n² = 441 ( take the square root of both sides )

n = \sqrt{441} = 21

The the identical numbers are 21

7 0
3 years ago
I have no idea what to do
Alexus [3.1K]

Answer:

A. $7.50 per hat

hope this helps :)

8 0
3 years ago
What are the coordinates of the vertices of the triangle under the translation (x y) (x + 1 y − 4)
musickatia [10]

Answer:

Hi! You didn't really provide a shape which would allow me to explain this much more easily but it's okay. The way to find the translation is very simple. Find the plotted points of the original figure, and make sure you label them and their coordinates so you know where they are. Then, to graph the translation, using those original coordinates, add one to all of the X's, and subtract four from all of the Y's. That will allow you to see what your prime picture will look like.

If this is still confusing, let me know and I'll be happy to further explain.

7 0
4 years ago
You are given that <img src="https://tex.z-dn.net/?f=sin%28A%29%20%3D%20-%5Cfrac%7B7%7D%7B25%7D" id="TexFormula1" title="sin(A)
Elza [17]

Answer:

- \frac{204}{325}

Step-by-step explanation:

Using the addition formula for cosine

cos(A + B) = cosAcosB - sinAsinB

Given sin A = - \frac{7}{25} = \frac{opposite}{hypotenuse} and in fourth quadrant, then

the triangle is a 7 - 24- 25 right triangle with adjacent side 24

In fourth quadrant cosine ratio is positive , thus

cos A = \frac{adjacent}{hypotenuse} = \frac{24}{25}

------------------------------------------------------------------

Given sin B = - \frac{12}{13} = \frac{opposite}{hypotenuse} and in third quadrant, then

the triangle is a 5- 12- 13 right triangle with adjacent side 5

In third quadrant cosine ratio is negative, thus

cos B = \frac{adjacent}{hypotenuse} = - \frac{5}{13}

Thus

cosAcosB - sinAsinB

= (\frac{24}{25} × - \frac{5}{13} ) - (- \frac{7}{25} × - \frac{12}{13} )

= - \frac{120}{325} - \frac{84}{325}

= - \frac{204}{325}

4 0
3 years ago
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