Cosα=adjacent side divided by the hypotenuse
cosA=24/26=12/13
cosB=10/26=5/13
You just need to subtract out the three checks that didn't clear on her last statement.
$324.18
($15.00)
($77.49)
($124.28)
________
$107.41 Total she should have had before her deposit
($487.38) Balance she had after her deposit
_______
$379.97 is how much of a deposit she made
Let y=total cost
We have 4 friends that paid an extra $6 each and 4 friends that paid regular admission.
Friends that paid extra= 4(x+6)
Friends that paid regular= 4x
Now we need to add those together.
y= 4(x+6) + 4x
Distribute the 4
y= (4*x) + (4*6) +4x
y=4x + 24 +4x
y=8x + 24
Hope this helps!! :)
Multiply the original DE by xy:
xy2(1+x2y4+1−−−−−−−√)dx+2x2ydy=0(1)
Let v=xy2, so that dv=y2dx+2xydy. Then (1) becomes
x(y2dx+2xydy)+xy2x2y4+1−−−−−−−√dxxdv+vv2+1−−−−−√dx=0=0
This final equation is easily recognized as separable:
dxxln|x|+CKxvKx2y2−1K2x4y4−2Kx2y2y2=−dvvv2+1−−−−−√=ln∣∣∣v2+1−−−−−√+1v∣∣∣=v2+1−−−−−√+1=x2y4+1−−−−−−−√=x2y4=2KK2x2−1integrate both sides
Answer: B
<u>Step-by-step explanation:</u>
In order to get the best representative sample, you should choose the widest range of students, which is from a random sample of all students.
(A) Choosing from only the 6th graders, eliminates the choices the other grade-level students would choose.
(C) Choosing only from students who participate in after-school activities, eliminates the choices the other students would choose.
(D) Chhosing only from students not participating in the fundraiser is silly since you want to know what the students participating in the fundraiser would choose.
The only possible option is B - students from all grades, regardless of whether or not they participate in after-school activities.