Percent Change = New Value − Old Value|Old Value| × 100%
Example: There were 200 customers yesterday, and 240 today:
240 − 200|200|× 100% = 40200 × 100% = 20%
A 20% increase.
Percent Error = |Approximate Value − Exact Value||Exact Value| × 100%
Example: I thought 70 people would turn up to the concert, but in fact 80 did!
|70 − 80||80| × 100% = 1080 × 100% = 12.5%
I was in error by 12.5%
(Without using the absolute value, the error is −12.5%, meaning I under-estimated the value)
The difference between the two is that one states factual calculations and the other is a theoretical guess
![\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}\qquad \begin{cases} r=radius\\ \theta =angle\ in\\ \qquad degrees\\ ------\\ r=6\\ s=10 \end{cases}\implies 10=\cfrac{\theta \pi 6}{180}\implies \cfrac{180\cdot 10}{6\pi }=\theta \\\\\\ \cfrac{300}{\pi }=\theta \implies 95.49^o\approx \theta](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barc%27s%20length%7D%5C%5C%5C%5C%0As%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%7D%7B180%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0A%5Ctheta%20%3Dangle%5C%20in%5C%5C%0A%5Cqquad%20degrees%5C%5C%0A------%5C%5C%0Ar%3D6%5C%5C%0As%3D10%0A%5Cend%7Bcases%7D%5Cimplies%2010%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%206%7D%7B180%7D%5Cimplies%20%5Ccfrac%7B180%5Ccdot%2010%7D%7B6%5Cpi%20%7D%3D%5Ctheta%20%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B300%7D%7B%5Cpi%20%7D%3D%5Ctheta%20%5Cimplies%2095.49%5Eo%5Capprox%20%5Ctheta%20)
now, the circle of the clock has 360°, if we divide it by 60(minutes), we get 360/60, just 6° for each minute.
now, if there are 6° in 1 minute, how many minutes in 95.49°?
well, just 95.49/6 or about 15.92 minutes, I take it you can round it up to 16 minutes.
so 16 minutes since noon, so is about 12:16, about time get the silverware for lunch.
Answer:
2) Equation 1 and Equation 2 have the same number of solutions.
Step-by-step explanation:
The two given equations are
1) 15x + 6 = 41 and 2) 2x + 13 = 28
Solving both equations, we get
Solving (1) : 15x + 6 = 41 ⇒ 15x = 41 - 6 = 35
or, x = 35/15 ⇒ x = 7/3
Solving (2) : 2x + 13 = 28⇒ 2x = 28 - 13 = 15
or, x = 15/2 ⇒ x = 15/2
So, from above solutions we can say that Equation 1 and Equation 2 have the same number of UNIQUE solution.