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2 years ago

PLS HURRY I NEED AN EXPLANATION!!!!

2 answers:

8 0

Answer: so if you have a right triangle and only know the horizontal and vertical lines you would which equal 13 and 12 you would find those squared which are, 169 and 144. Add those together. 313. Then get the square root of 313. Which is rounded 17.7. So the answer to the hypotenuse is 17.7

Step-by-step explanation:

neonofarm [45]2 years ago

4 0

Answer:

c = √(a² + b²)

Step-by-step explanation:

c=√a2+b2

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Mary buys a 10-meter spool of thread for sewing. She uses 210 centimeters. How much is left on the spool in centimeters?

Margaret [11]

100 cm = 1 meter

210 cm = 2.1 meters (multiply both sides by 2.1)

Mary uses 2.1 meters of thread so far, meaning she has 10-2.1 = 7.9 meters left

7.9 meters = (7.9 m)*(100 cm/1 m) = 790 cm

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Alternate route:

10 meters = (10 m)*(100 cm/1 m) = 1000 cm

Mary uses 210 cm out of 1000 cm total, so she has 1000-210 = 790 cm left.

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<h3>Answer: 790 cm</h3>

6 0

3 years ago

What is the slope of the line in this equation 2x – 4y = 6?

fomenos

Pretty sure it’s -4/2

4 0

3 years ago

Read 2 more answers

Help!! I need to find X of the triangle—

FrozenT [24]

Answer:

Step-by-step explanation:

i think plz give brainleast

7 0

2 years ago

I need help with this problem

zloy xaker [14]

2.3 x 10^-3 * 4.2 x 10^2 =
.0023 * 420 =
<span> <span> <span> 0.966 </span> </span> </span>

3 0

2 years ago

Read 2 more answers

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$

$\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}$

8 0

1 year ago