Answer: friend?...
Step-by-step explanation:...
Answer:

Step-by-step explanation:
We want to find

This can be rewritten as;


Recall that; 

We evaluate now to obtain;

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

The area of the triangle is given by the following formula:

Where "b" is the base and "h" is its height. Replacing the values:

The total area is the sum of both areas:

replacing the areas:
I know that B is orthographic.
D is isometric.
A is a net.
C is none.