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Anna11 [10]
3 years ago
11

Find the sum of this infinite geometric series 1/7+ 1/49 + 1/343

Mathematics
2 answers:
pochemuha3 years ago
6 0
-1/6 or -1/8 or 1/6 or 1/8 one of these for sure 

marusya05 [52]3 years ago
5 0

The sum of the infinite geometric series

a+ar+ar^2+... where a is the first term and r common ratio -1 is \frac{a}{1-r}.

Here the given series is \frac{1}{7} +\frac{1}{49} +\frac{1}{343} +....

Here a=1,r=\frac{1}{7}. The sum of the infinite geometric series is

\frac{1}{1-1/7} =\frac{7}{6}

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In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is
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<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

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Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

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Step-by-step explanation:

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