Answer:
$460.38
Step-by-step explanation:
Use the exponential decay formula, y = C(1 - r)^t
Plug in the original price, depreciation rate, and amount of time:
y = 20000(0.875)^11
y = 460.38
So, the car's value after 11 years will be $460.38
Answer: why?
Step-by-step explanation:
In base 12, A represents 10 and B represents 11. So
7B6A (base 12) = 7*12^3 + 11*12^2 + 6*12^1 + 10*12^0
7B6A (base 12) = 12,096 + 1,584 + 72 + 10
7B6A (base 12) = 13,762 (base 10)
Answer:
a. ∫ xSinx dx
iii. integration by parts
u =x and dv= sinx
b. ∫ x⁴/(1+x³). dx
ii. neither
Long division is an option here before integration is done
c. ∫ x⁴. e^x³. dx
i. substitution
where u = x⁵
d. ∫x⁴ cos(x⁵). dx
i. substitution
where u = x⁵
e. ∫1/√9x+1 .dx
i. substitution
where u = 9x+1
