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2 years ago

Please help! I will mark brainliest for correct answer and explanation! please and thank you in advance!

Mathematics

2 answers:

yulyashka [42]2 years ago

8 0

Answer:

point form (4,4)

equation form x= 4, y= 4

Step-by-step explanation:

kifflom [539]2 years ago

6 0

Answer: Y = 4, X=4 (4,4)

Step-by-step explanation: You must multiply both equations so the leading coefficient cancels out. I’m multiplying both equations by both coefficients so I multiply the entire first equation by -2 so the first equation will be the negative coefficient and the second equation will be multiplied by positive 9 so the negative and positive equations cancel out.

STEPS IN MATH:

1. (9x-8y=4) -2 = -18x + 16y = -8

(2x-3y=-4)9 = 18x-27y= -36

2. ADD THESE EQUATIONS TOGETHER NOW

-18x+16y=-8

+ 18x-27y=-36

0-11y= -44

-11y=-44

DIVIDE -44 by -11y

The final answer is Y= 4

NOW pick an equation to plug in y to, any equation works

I chose the first one, so 9x-8(4)=4

9x-32=4

9x=36

x=4

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3 years ago

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3 years ago

What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$

Substituting,

$E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}$

Factoring out the n and one p from the above expression:

$E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}$

Representing k=x-1 in the above gives us:

$E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}$

This can then be written by the Binomial Formula as:

$E[ X ] = (np) (p +(1 - p))^{n -1 }= np.$

5 0

3 years ago

What is (-8)to the power of 2 equal??

Vladimir79 [104]

(-8)^2
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64

Hope this helps!

3 0

2 years ago

Read 2 more answers

pasha is thinking of a number such that when twice the number is added to three times one more than the number she gets the same

Lelechka [254]

This is the equation made from the problem where x=mystery number
2x+3(x+1)=4(x-1)

Now let's solve for x!

We start by distributing 3 into (X+1)

3(x)=3x and 3(1)=3

Now our equation is 2x+3x+3=4(x-1)

Let's combine both x values on the left side of the equation: 2x + 3x=5x

We now have 5x+3=4(x-1)

Let's distribute 4 into (x-1)

4(x)=4x and 4(-1)=-4

Now our equation is 5x+3=4x-4

subtract 3 form both sides

5x=4x-7

subtract 4x from both sides

x=-7

Yay! So the number she is thinking of is -7!

5 0

3 years ago

Read 2 more answers