Answer: the length of string that been let out to fly the kite this high is 172.89 ft
Step-by-step explanation:
The length of string attached to the kite, the vertical height of the kite above the ground and the ground distance forms a right angle triangle.
With an angle of 57 degrees, the length of the string that is attached to the kite represents the hypotenuse of the right angle triangle.
The height of the kite above the ground represents the opposite side of the triangle
To determine h, the length of the string that has been let out to fly the kite this high, we would apply the
Sine trigonometric ratio which is expressed as
Sine θ = opposite side/hypotenuse
Sin 57 = 145/h
h = 145/Sin57 = 145/0.8387
h = 172.89
Answer:
volume before window is taken out = lwh
volume of window is w^3
total volume is..... as given in pic
this is right
...............
Answer: The answer is (B) ∠SYD.
Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.
We are given four angles, out of which one should be chosen which is congruent to ∠CXP.
The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.
For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.
Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.
Thus, we have
∠CXP ≅ ∠SYD.
So, option (B) is correct.
Origin = (0,0)
To find the units of distance subtract the given pair from origin
(0,4) - (0,0) = 4
Answer:
(3•22g4h5)
Step-by-step explanation:
Step 1: ((3gh2 • 4) • g3) • h3
Step 2: ((3•22gh2) • g3) • h3
Step 3: 3.1 h2 multiplied by h3 = h(2 + 3) = h5
Final answer: (3•22g4h5)
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