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Dafna11 [192]
3 years ago
7

How do you solve: secx=-5/2, tanx<0 Find all six trig functions

Mathematics
1 answer:
Brut [27]3 years ago
5 0

Answer:

sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21

Step-by-step explanation:

During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.

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Point B ∈ AC. Find the length of segments AB and BC if AC = 20 cm and: AB:BC = 3:7
madam [21]

Answer:

Length of AB  = 6 cm

Length of the segment BC =  14 cm

Step-by-step explanation:

Here, B is a point on a segment AC.

AB : BC = 3:7

Length of the segment AC = 20 cm

Now, let the common ratio between the segment is x.

So, the length of AB = 3 x , and Length of BC = 7 x

Now, AB + BC = AC

⇒  3x + 7x = 20

or, 10 x = 20

or, x = 2

Hence, the length of AB = 3 x = 3 x 2 = 6 cm

and the length of the segment BC = 7x =  7 x 2 =  14 cm

7 0
4 years ago
Read 2 more answers
The employees of a company were surveyed on questions regarding their educational background (college degree or no college degre
taurus [48]

Answer: D) 0.733.

Step-by-step explanation:

Let C denotes the number of employees having college degree and S denote the number of employees are single.

We are given ,

Total = 600 , n(C)=400  , n(S)=100 , n(C∩S)=60

Then,

n(C\cup S)=n(C)+n(S)-n(C\cap S)\\\\=400+100-60=440

Now, the probability that an employee of the company is single or has a college degree is

P(C\cup S)=\dfrac{n(C\cup S)}{\text{Total}}\\\\=\dfrac{440}{600}=0.733333333\approx0.733

Hence, the probability that an employee of the company is single or has a college degree is 0.733

8 0
3 years ago
An angle is formed by two rays that share the same endpoint? True or False
Gre4nikov [31]
Im pretty sure its true

8 0
3 years ago
Read 2 more answers
Simplify the following monomials pls
velikii [3]

Answer:

1.) a^4b

2.) p^3q^4

3.) 2n^42n^4

4.) 5xy^2z

5.) 2a^3b^5

I hope this helps:

4 0
3 years ago
The reading on a car speedometer has 1.6% maximum error the speed limit on the road is 65 miles per hour
nasty-shy [4]

Answer:

For A) it is possible that the speed  the cat is going over the speed limit

For B) The statement is false as if the error is negative, the speed of the car will be less than the speed limit.

Step-by-step explanation:

Data provided in the question:

Maximum error  on a car speedometer = 1.6% = 0.016

Maximum Speed limit on the road = 65 miles per hour

Now,

The error will be ± 1.6%

Now,

When the speedometer reads 64 miles per hour

The possible speed of the car can be

64 miles per hour + Error

= 64 + [0.016 × 64]

= 64 + 1.024

= 65.024 miles per hour

or

The speed can be

64 miles per hour - Error

= 64 - [0.016 × 64]

= 64 - 1.024

= 62.976 miles per hour

Hence,

For A) it is possible that the speed  the cat is going over the speed limit

For B) The statement is false as if the error is negative, the speed of the car will be less than the speed limit.

3 0
4 years ago
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