How do you solve: secx=-5/2, tanx<0
Find all six trig functions
1 answer:
Answer:
sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21
Step-by-step explanation:
During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.
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Answer:
2/11
Step-by-step explanation:
6 = 2 x 3
6/11 x 1/3
= ( 6 x 1 )/( 11 x 3 )
= ( 2 x 3 x 1 )/( 11 x 3 )
Cancel 3 in both numerator and denominator.
= ( 2 x 1 )/( 11 )
= 2/11
No
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