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3 years ago

The weights of 3 puppies at one week old were 6.5 ounces, 7.3 ounces, and 6.4 ounces. If each

Mathematics

1 answer:

photoshop1234 [79]3 years ago

8 0

The answers are 8.6 ounces, 9.4 ounces, and 8.5 ounces

Explanation:

To find how much each puppy weights simply add the weight they gained (2.1 ounces) to the weight of each puppy at one week old. The process to add the weights is shown below:

First Puppy

6.5 ounces (weight at one week old) + 2.1 ounces (weight gained)

Align both numbers using the period as the reference and add

6.5

+ 2.1

8.6

The weigh of the first puppy is 8.6 ounces which can be rounded as 9 ounces (integer)

Second Puppy

Now, repeat the process

7.3 ounces + 2.1 ounces

7.3

+ 2.1

9.4

The weigh of this puppy is 9.4 ounces or 9 ounces (integer) if rounded

Third Puppy

6.4 ounces + 2.1 ounces

6.4

+ 2.1

8.5

The weight of the third puppy is 8.5 ounces which can be rounded as 8 ounces or 9 ounces (integers) depending on the rounding method.

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3 years ago

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Over [174]

Answer:

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Step-by-step explanation:

Using Law of Cosine, you can find KM. Then using Law of Sines, you can find the angle of M. Find the sum of angle M and 90. Then subtract the total of that to 180 to fine angle K. (sidenote: your angle K should be bigger then angle M since the side measurement of K is larger than M.)

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3 years ago

The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func

katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle ( $\frac{1}{3},\frac{1}4$ ).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A( $\frac{1}{3},\frac{1}4$ )

Let O be the origin i.e. (0,0)

Point B will be ( $\frac{1}{3},0$ )

Now, let us consider the right angled triangle $\triangle OBA$ :

Sides:

$Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}$

Using Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}$