The sum of two numbers is 40 and their difference is 6.5, what is their product? show work please
1 answer:
Let b>a,
a+b=40 so we can say a=40-b
We are told that b-a=6.5, using a found above in the equation gives us:
b-(40-b)=6.5
b-40+b=6.5
2b-40=6.5
2b=46.5
b=23.25, and since a=40-b
a=40-23.25
a=16.75
So a=16.75 and b=23.25
check...
16.75+23.25=40, 40=40
23.25-16.75=6.5, 6.5=6.5
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<A = <C = 73
<B = 180 - (<A + C)
6x + 4 = 180 - 2(73)
6x + 4 = 180 - 146
6x + 4 = 34
6x = 30
x = 5
answer
x = 5
F(2)= 4(16) - 6(4) + 8(2) - 15
F(2)= 64 -24 + 16 - 15
F(2)= 41
Step-by-step explanation:
tan (0)=sin (0)/cos (0)
cos (0)=sin (0)/tan (0)
= -4/5/4/3
= -3/5
