Question

Find the perimeter of quadrilateral ABCD with vertices A=(1,1) B=(4,4) C=(7,1) D=(4,-2). Explain your answer.​

Answer 1

we have the coordinates of ABCD

there are 2 ways of doing this one is you find the distance of ab, bc, cd and da and then add the answers together. there is another way but i dont remember it properly so i am just gonna do it this way

distance between 2 point = $\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

AB

$d = \sqrt {(4 - 1)^2 + (4 - 1)^2}$

$d = \sqrt {(3)^2 + (3)^2}$

$d = \sqrt {9 + 9}$

$d = \sqrt 18$

AB = 4.24

now repeat the same with all

BC= 4.24

CD= 4.24

DA= 4.24

so its a square with all the same sides so perimeter is 4 x 4.24

perimeter is 16.96

hope this helps

mark me as brainliest please