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3 years ago

8x-1<15 NO one will help plss someone hellpppp

Mathematics

2 answers:

romanna [79]3 years ago

7 0

Answer:

x < 2

Step-by-step explanation:

8x -1 < 15

8x -1 (+ 1) < 15 (+ 1)

8x < 16

$\frac{8x}{8} < \frac{16}{8}$

x < 2

hodyreva [135]3 years ago

4 0

The answer will be X < 2

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3 years ago

a company owns two dealerships, both of which sell cars and trucks. the first dealership sells a total of 164 cars and trucks. t

OLEGan [10]

Answer:

294 cars.

Step-by-step explanation:

Let x be the number of cars and y be the number of trucks.

We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:

$x+y=164...(1)$

The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.

Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:

$2x+\frac{y}{2}=229...(2)$

We can see that total number of cars sold on two dealerships will be $x+2x=3x$ .

We will use substitution method to solve for x. From equation (1) we will get,

$y=164-x$

Substituting this value in equation (2) we will get,

$2x+\frac{164-x}{2}=229$

Now let us have a common denominator.

$\frac{4x}{2}+\frac{164-x}{2}=229$

$\frac{4x+164-x}{2}=229$

Upon multiplying both sides of our equation by 2 we will get,

$2\times \frac{4x+164-x}{2}=2\times 229$

$4x+164-x=458$

$4x+164-164-x=458-164$

$4x-x=458-164$

$3x=294$

Therefore, the total number of cars sold by two dealerships is 294.

7 0

3 years ago

Will mark BRAINLIEST!

vazorg [7]

count them all together
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3 years ago

When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

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3 years ago

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makvit [3.9K]

Answer:

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Step-by-step explanation: i got it right PERIOD PURRRRR

3 0

2 years ago

Read 2 more answers