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3 years ago

5th grade math. Correct answer will be marked brainliest.

Mathematics

1 answer:

vitfil [10]3 years ago

4 0

Answer: The answer would be (0,3)

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1 hundreth is how many times greater than 1 thousandths? Pls helppp

Verdich [7]

Answer:

1 hundreths is 10 times greater than 1 thousandths.

Step-by-step explanation:

just like 100 is ten times greater than 10.

4 0

3 years ago

Read 2 more answers

1. Alan got 80% in his math test, Jorden got one-fifth more, what is the mark of Jorden?

nignag [31]

Answer:

1. 96%

2. $6000

3. 176

4. 20%

Step-by-step explanation:

1. 1/5 of 80% is 16%. 80+16=96

2. 25% of 8000 is 2000. 8000-2000= 6000.

3. 10% increase of 200 is 20. 20+200=220. 20 percent of 220 is 44. 220-44=176

4. if you increase the original salary by 20%, then decreasing it by 20% of the new salary will give you the old salary.

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2 years ago

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How to write the number 1.39-1.14 in word form

9966 [12]

0.25 which is a quarter.

3 0

3 years ago

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Match each equation with a diagram:

Flura [38]

Answer:

a= 3

b=3

c=3

d=3

Step-by-step explanation:

12-?=4, or it could also be like 12-3=4. so thats how i got it.

hope it helps. i tried. hope i did it correct if thats what u need

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3 years ago

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The quadratic function g(x) = a.ca + bx+c has the

Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

$f(x)=ax^2+bx+c$

Here we know that the leading coefficient $a=1$ so we reduce our equation to:

$g(x)=x^2+bx+c$

The roots are those values at which $g(x)=0$

So:

$x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\$

$Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0$

So we have:

$(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}$

Finding c from (1):

$33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}$

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0

3 years ago