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2 years ago

Find the domain and range of f(x)=4*(1/2)^x

Mathematics

1 answer:

jolli1 [7]2 years ago

6 0

Domain is the set of x-values and range is the set of y-values.

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Pls help and a give u a brilliant

fomenos

Answer:

Instead of 16 write 36

Step-by-step explanation:

when we see this carefully 4/6= 24/16

This is an equivalent fraction

when we multiply 4×6 we get 24 so we must multiply 6 with 6 . so the answer is 36.

4 0

3 years ago

At a historical landmark, candles are used to simulate an authentic atmosphere. A volunteer is currently putting new candles in

myrzilka [38]

Answer:

Each small candleholder holds 3 candles, and each large one holds 5 candles.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of candles that a small candleholder holds.

y is the number of candles that a large candleholder holds.

24 small candle holders and 3 large candle holders, using a total of 87 candles.

This means that

$24x + 3y = 87$

Simplifying by 3

$8x + y = 29$

$y = 29 - 8x$

14 small candle holders and 7 large candle holders, for a total of 77 candles.

This means that $14x + 7y = 77$

Simplifying by 7

$2x + y = 11$

$y = 11 - 2x$

Since $y = 29 - 8x$

$11 - 2x = 29 - 8x$

$6x = 18$

$x = \frac{18}{6}$

$x = 3$

$y = 29 - 8x = 29 - 8*3 = 29 - 24 = 5$

Each small candleholder holds 3 candles, and each large one holds 5 candles.

5 0

2 years ago

HELP ASAP H(x)=-6x+8 G(x)=10-2x H(G(x))

galben [10]

Answer:

H(G(x)) = 12x - 52

Step-by-step explanation:

We are given the following two functions:

$H ( x ) = - 6 x + 8$

$G ( x ) = 1 0 - 2 x$

And we are to find the value of H(G(x)).

For that, we will apply the function of H on the function of G.

$H(G(x))=H(10-2x)$

$H ( G ( x ) ) = - 6 ( 1 0 - 2 x ) + 8$

$H(G(x))=-60+12x+8$

H(G(x)) = 12x - 52

7 0

2 years ago

A net force acting on a 5.0 kg box produces an acceleration of 4.2 m/s2. What

liq [111]

Answer:

14 N

Step-by-step explanation:

Let the mass of the box be m.

F = ma → F = 5 x 4.2 = 21 N

When mass = 2.8 kg, let the acceleration is a. For same force:

=> 21 = a x 2.8

=> 21/2.8 = a

=> 7.5 m/s² = a

6 0

2 years ago

Read 2 more answers

The original quantity is 10 and the new quantity

kobusy [5.1K]

Answer:

30 %

Step-by-step explanation:

Assumption: the increase is to be expressed as a percentage of 10.

We change from 10 to 13 so the increase is 3 We now need to change this into a percentage.

In fraction form we have increase Original value → 3 10 But we need to change this into the form some number 100 Let the unknown value be x giving: 3 10 ≡ some number 100 = x 100 To change the 10 from 3 10 into 100 we multiply by 10 Multiply by 1 and you do not change the value.

However, 1 comes in many forms.

3 10 × 1 = 3 10 × 10 10 = 30 100 This is the same as 30 × 1 100 but 1 100 is the same as %.

So 30 100 → 30 %

7 0

2 years ago