The answer is <span> tunnel mode encryption. This</span><span> describes encryption that protects the entire original ip packet's header and payload. A tunnel mode encryption </span><span>protects the internal routing information by encrypting the IP header of the original packet. The original packet is encapsulated by a another set of IP headers. .<span>Additional headers are added to the packet; so the payload MSS is less.</span></span>
Answer:
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Answer:
Here you go :)
Explanation:
Change this however you'd like:
array = []
for n in range(10):
x = int(input("Enter integer: "))
array.append(x)
dup = set(array)
print(", ".join(str(i) for i in dup))
We all know that there are 26 letters available in the alphabet and there are just 5 even numbers between 0 and 9. We are now given the situation of how many passwords can we make out of the criteria of having 5 letters that cannot be repeated and 4 even digits from 0-9. We cannot repeat the numbers and letters, thus our password will look something like this, LLLLLNNNN, where L is a letter and N is a number. Let us note that we cannot use the characters and digits more than once.This is how we will solve the probable number of passwords.
26 x 25 x 24 x 23 x 22 x 5 x 4 x 3 x 2
When we compute this formula, we will have the total number of possible passwords:
947,232,000.00
There are 947,232,000 possible passwords based on the given criteria.