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77julia77 [94]
3 years ago
5

Solve the compound inequality. 6 – x > 15 or 2x – 9 ≥ 3 A. x > 9 or x ≤ 6 B. x < 9 or x ≥ –6 C. x > –9 or x ≤ –6 D.

x < –9 or x ≥ 6
Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

Step-by-step explanation:

Solve the compound inequality. 6 – x > 15 or 2x – 9 ≥ 3 A. x > 9 or x ≤ 6 B. x < 9 or x ≥ –6 C. x > –9 or x ≤ –6 D. x < –9 or x ≥ 6

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Pls answer this now pls i beg u i need to past it on school :) thank you so much​
ELEN [110]

Answer: 13.85kg Hope this helps, please consider making me Brainliest.

Step-by-step explanation:

Let's add! 7 1/4 + 6 3/5 = 7.25 + 6.6

7 + 6 + .25 + .6 = 13 + .85 =

13.85

8 0
2 years ago
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20 pts awarded and brainliest chosen!!!!
g100num [7]

Answer:

D.  x <= -3 or   x >= 5

Step-by-step explanation:

3 | x-1 | > = 12

3(x - 1) >= 12

3x - 3 >= 12

3x >= 15

 x >= 5

or

-3(x - 1) >=  12

-3x + 3 >= 12

-3x >= 9

  x <= -3

Answer

x <= -3 or   x >= 5

4 0
3 years ago
Please help ASAP!<br><br> what is x=-b/2a?
valina [46]

This is the formula to solve for the vertex.

Example Question:

Find the vertex of y = -0.5x^2 + 100x

-b/2a = -100/2(-0.5) = -100/-1 = 100

The x coordinate of the vertex is 100.

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5 0
3 years ago
Is 3 times 2/7 greater or less than 3
inysia [295]

2/7 as a fraction rounds to 0.3

0.3 * 3 = 0.9

3 x 2/7 is less than 3

3 0
3 years ago
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What is the area of the composite figure
kati45 [8]

To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!

\boxed{ \sf \: area \: of \: square =side ^{2}  }

  • Side 3 metre

\rm \implies \: area = 3 ^{2}

\rm \implies9

<em>Thus, The area of 1st square is 9m²...</em>

  • The area of second square will be also 9m², because the sides of both squares are equal.

<h3>Now area of the reactangle⤵️</h3>

  • Length = 6m
  • Breadth = 7+3=10m

\sf \: area \: of \: rectangle = length \times breadtg

\tt \dashrightarrow \: area = 10 \times 3

\tt \dashrightarrow \: area = 30m ^{2}

<em>Thus, The area of rectangle is 30m²....</em>

  • Now, Add area of all the figures to get the total area.

\bf \:total \: area = 9 + 9 + 30 \\   \bf= 48m {}^{2}

<h3><em>Therefore, The total area of the composite figure is 48m²...~</em></h3>
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2 years ago
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